Question
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he bank offers a rate of \( 11 \% \), compoundec continuously, on any deposit that will not be removed for a minimum of 20 years. If you invest \( \$ 10,000 \) with the bank, how much money can you expect to have in the account after 20 years?

Ask by Cook Savage. in the United States
Jan 23,2025

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Answer

After 20 years, you can expect to have approximately \$90,250 in your account.

Solution

To determine how much money you'll have in your account after 20 years with continuous compounding, we can use the formula for continuous compounding: \[ A = P \times e^{rt} \] Where: - \( A \) = the amount of money accumulated after \( t \) years, including interest. - \( P \) = the principal amount (\$10,000). - \( r \) = annual interest rate (11% or 0.11). - \( t \) = time the money is invested for (20 years). - \( e \) = the base of the natural logarithm (approximately 2.71828). Plugging in the values: \[ A = 10,000 \times e^{0.11 \times 20} \] \[ A = 10,000 \times e^{2.2} \] Calculating \( e^{2.2} \): \[ e^{2.2} \approx 9.0250135 \] Now, multiply this by the principal: \[ A \approx 10,000 \times 9.0250135 = 90,250.135 \] **So, after 20 years, you can expect to have approximately \$90,250 in your account.**

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Bonus Knowledge

To calculate the future value of an investment with continuous compounding, you can use the formula: \[ A = Pe^{rt} \] where: - \( A \) is the amount of money accumulated after time \( t \), - \( P \) is the principal amount (the initial investment), - \( r \) is the annual interest rate (decimal), and - \( t \) is the time the money is invested for, in years. In this case: - \( P = 10,000 \), - \( r = 0.11 \) (11% expressed as a decimal), - \( t = 20 \). Plugging in the values: \[ A = 10000 \times e^{(0.11 \times 20)} = 10000 \times e^{2.2} \] Using \( e^{2.2} \approx 9.025 \): \[ A \approx 10000 \times 9.025 \approx 90250 \] So, after 20 years, you can expect to have approximately \( \$ 90,250 \) in your account. Happy saving! 🎉💰

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