Solve the following system of equations graphically on the set of axes below. $$ \begin{array}{l} y=\frac{1}{2} x-5 \ x+y=1\end{array} $$

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Solve the system of equations $$ x+y=1; y=\frac{1}{2}x-5 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}x+y=1\y=\frac{1}{2}x-5\end{array}ight.$$
- step1: Substitute the value of $$y:$$
  $$x+\frac{1}{2}x-5=1$$
- step2: Add the terms:
  $$\frac{3}{2}x-5=1$$
- step3: Move the constant to the right side:
  $$\frac{3}{2}x=1+5$$
- step4: Add the numbers:
  $$\frac{3}{2}x=6$$
- step5: Multiply by the reciprocal:
  $$\frac{3}{2}x	imes \frac{2}{3}=6	imes \frac{2}{3}$$
- step6: Multiply:
  $$x=4$$
- step7: Substitute the value of $$x:$$
  $$y=\frac{1}{2}	imes 4-5$$
- step8: Simplify:
  $$y=-3$$
- step9: Calculate:
  $$\left\{ \begin{array}{l}x=4\y=-3\end{array}ight.$$
- step10: Check the solution:
  $$\left\{ \begin{array}{l}x=4\y=-3\end{array}ight.$$
- step11: Rewrite:
  $$\left(x,yight) = \left(4,-3ight)$$
The solution to the system of equations $$x+y=1$$ and $$y=\frac{1}{2}x-5$$ is $$x=4$$ and $$y=-3$$.

Therefore, the point of intersection of the two lines is $$(4, -3)$$.
The solution is $$x=4$$ and $$y=-3$$.

Solve the following system of equations graphically on the set of axes below.

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