Solve using substitution. $$ \begin{array}{l}10 x-8 y=18 \ x=5\end{array} $$

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Solve the system of equations $$ 10x-8y=18;x=5 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}10x-8y=18\x=5\end{array}ight.$$
- step1: Substitute the value of $$x:$$
  $$10	imes 5-8y=18$$
- step2: Simplify:
  $$50-8y=18$$
- step3: Move the constant to the right side:
  $$-8y=18-50$$
- step4: Subtract the numbers:
  $$-8y=-32$$
- step5: Change the signs:
  $$8y=32$$
- step6: Divide both sides:
  $$\frac{8y}{8}=\frac{32}{8}$$
- step7: Divide the numbers:
  $$y=4$$
- step8: Calculate:
  $$\left\{ \begin{array}{l}x=5\y=4\end{array}ight.$$
- step9: Check the solution:
  $$\left\{ \begin{array}{l}x=5\y=4\end{array}ight.$$
- step10: Rewrite:
  $$\left(x,yight) = \left(5,4ight)$$
The solution to the system of equations using substitution is $$ (x,y) = (5,4) $$.
$$ (x,y) = (5,4) $$

Solve using substitution.

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