Determine the equation of the line that passes through the points \( (2,-14) \) an \( (8,-68) \). Enter your equation in the form \( y=m x+b \), Simplify your answer completely.
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Extra Insights
To find the equation of the line that passes through the points \( (2,-14) \) and \( (8,-68) \), we first need to calculate the slope \( m \) using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting in the values from the points \( (x_1, y_1) = (2, -14) \) and \( (x_2, y_2) = (8, -68) \): \[ m = \frac{-68 - (-14)}{8 - 2} = \frac{-68 + 14}{6} = \frac{-54}{6} = -9 \] Now, using the slope-intercept form \( y = mx + b \), we substitute \( m = -9 \) along with one of the points to solve for \( b \). We'll use the point \( (2, -14) \): \[ -14 = -9(2) + b \] \[ -14 = -18 + b \] \[ b = -14 + 18 = 4 \] Now, we can write the equation of the line: \[ y = -9x + 4 \] So, the equation of the line is \( y = -9x + 4 \).