If 24 assemblers can complete a certain job in 6 hours, how long will the same job take if the number of assemblers is cut back to 18 ?

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To determine how long the job will take with 18 assemblers instead of 24, we can use the concept of **inverse proportionality**. Here's the step-by-step reasoning:

1. **Calculate the Total Work:**
   - If 24 assemblers complete the job in 6 hours, the total work can be expressed as:
     $$
     \text{Total Work} = \text{Number of Assemblers} \times \text{Time} = 24 \times 6 = 144 \text{ assembler-hours}
     $$

2. **Determine the Time with 18 Assemblers:**
   - Let $$ t $$ be the time it takes for 18 assemblers to complete the same 144 assembler-hours of work.
     $$
     18 \times t = 144
     $$
   - Solve for $$ t $$:
     $$
     t = \frac{144}{18} = 8 \text{ hours}
     $$

**Answer:** 8 hours
It will take 8 hours for 18 assemblers to complete the job.

If 24 assemblers can complete a certain job in 6 hours, how long will the same job take if the number of assemblers is cut back to 18 ?

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