\begin{tabular}{l|l} Finding & \( \begin{array}{l}\text { To find the } x \text {-intercept of an equation, set } y \text { equal to } 0 \text { and solve for } x \\ \text { To find the } y \text {-intercept of an equation, set } x \text { equal to } 0 \text { and solve for } y \\ \text { You can use these points to graph the equation. } \\ \text { cepts }\end{array} \) \\ \( \begin{array}{l}\text { Example: Find the } x \text {-and } y \text {-intercepts of the equation } y=-2 x+5\end{array} \) \\ & \end{tabular}

To find the \( x \)-intercept and \( y \)-intercept of the equation \( y = -2x + 5 \), we will follow the steps outlined in your table. ### Step 1: Finding the \( x \)-intercept To find the \( x \)-intercept, we set \( y = 0 \) and solve for \( x \). \[ 0 = -2x + 5 \] Now, we will solve for \( x \): \[ -2x = -5 \] Dividing both sides by \(-2\): \[ x = \frac{5}{2} \] Thus, the \( x \)-intercept is \( \left( \frac{5}{2}, 0 \right) \). ### Step 2: Finding the \( y \)-intercept To find the \( y \)-intercept, we set \( x = 0 \) and solve for \( y \). \[ y = -2(0) + 5 \] This simplifies to: \[ y = 5 \] Thus, the \( y \)-intercept is \( (0, 5) \). ### Summary of Intercepts - The \( x \)-intercept is \( \left( \frac{5}{2}, 0 \right) \). - The \( y \)-intercept is \( (0, 5) \). These points can be used to graph the equation \( y = -2x + 5 \).