\begin{tabular}{l} Rewrite this expression into Standard Form \ $$ \qquad 4(x+2)^{2}-64 $$ \ $$ 4 x^{2}+16 x-80 $$ \ $$ 4 x^{2}+16 x-48 $$ \ $$ 4 x^{2}+8 x-64 $$ \ $$ 4 x^{2}-16 x+48 $$ \ \hline\end{tabular}

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To rewrite the expression $$ 4(x+2)^{2} - 64 $$ into standard form, follow these steps:

1. **Expand the squared term:**
   $$
   (x + 2)^2 = x^2 + 4x + 4
   $$

2. **Multiply by 4:**
   $$
   4(x^2 + 4x + 4) = 4x^2 + 16x + 16
   $$

3. **Subtract 64:**
   $$
   4x^2 + 16x + 16 - 64 = 4x^2 + 16x - 48
   $$

So, the expression in standard form is:
$$
4x^{2} + 16x - 48
$$

**Answer:** $$ 4 x^{2}+16 x-48 $$
The standard form of the expression is $$ 4x^{2} + 16x - 48 $$.

\begin{tabular}{l} Rewrite this expression into Standard Form \\ \( \qquad 4(x+2)^{2}-64 \) \\ \( 4 x^{2}+16 x-80 \) \\ \( 4 x^{2}+16 x-48 \) \\ \( 4 x^{2}+8 x-64 \) \\ \( 4 x^{2}-16 x+48 \) \\ \hline\end{tabular}

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