\begin{tabular}{l} Rewrite this expression into Standard Form \\ \( \qquad 4(x+2)^{2}-64 \) \\ \( 4 x^{2}+16 x-80 \) \\ \( 4 x^{2}+16 x-48 \) \\ \( 4 x^{2}+8 x-64 \) \\ \( 4 x^{2}-16 x+48 \) \\ \hline\end{tabular}

To rewrite the expression \( 4(x+2)^{2}-64 \) into standard form, let's first expand the square and then simplify: 1. Start with the expression: \( 4(x+2)^{2}-64 \). 2. Expand \( (x+2)^{2} \): \( (x+2)(x+2) = x^2 + 4x + 4 \). 3. Now, multiplying by 4: \( 4(x^2 + 4x + 4) = 4x^2 + 16x + 16 \). 4. Subtract 64 from this: \( 4x^2 + 16x + 16 - 64 = 4x^2 + 16x - 48 \). So the expression in standard form is \( 4x^2 + 16x - 48 \).