Question
- Consider the two independent rolls of a fair 6 -sided dice. What is the
probability of getting at least one 6 given the two rolls land on different
numbers?
probability of getting at least one 6 given the two rolls land on different
numbers?
Ask by Vaughan Bradley. in Pakistan
Jan 22,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The probability of getting at least one 6, given that the two rolls are different, is 1⁄3.
Solution
To determine the probability of getting at least one 6 given that the two rolls land on different numbers, we’ll use conditional probability.
Definitions:
- Event A: At least one of the two rolls is a 6.
- Event B: The two rolls land on different numbers.
We need to compute
, which is the probability of Event A occurring given that Event B has occurred. The formula for conditional probability is:
Step 1: Calculate
- Probability that the two rolls are different.
- Total possible outcomes when rolling two 6-sided dice:
. - Favorable outcomes for different numbers: Total outcomes minus the outcomes where both dice show the same number. There are 6 outcomes where both dice show the same number (e.g., (1,1), (2,2), …, (6,6)).
Step 2: Calculate
- Probability that at least one 6 occurs and the two rolls are different.
- Cases where at least one 6 occurs and the numbers are different:
- First die is 6 and the second die is not 6:
outcomes. - Second die is 6 and the first die is not 6:
outcomes.
- First die is 6 and the second die is not 6:
Step 3: Compute the Conditional Probability
.
Final Answer:
The probability is 1⁄3.
Answered by UpStudy AI and reviewed by a Professional Tutor
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Bonus Knowledge
To solve this problem, we first determine the total number of outcomes when rolling two 6-sided dice. There are 36 possible outcomes (6 sides on the first die multiplied by 6 sides on the second). However, we only want the cases where the dice show different numbers. There are 6 choices for the first die and 5 for the second die (to ensure it’s different), giving us 30 pairs.
Next, we find the cases where at least one die shows a 6. The possible outcomes where they differ and at least one die is a 6 are (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (1, 6), (2, 6), (3, 6), (4, 6), and (5, 6). That’s a total of 10 favorable outcomes.
Thus, the probability of getting at least one 6, given that the two rolls are different, is the number of favorable outcomes divided by the total different outcomes:
So, the probability is
.