Question
Give the degree of the polynomial. \[ 16 w^{7} y^{4} u^{3}+6-5 y^{12}-u^{11} w \]
Ask by Ingram Matthews. in the United States
Jan 23,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The degree of the polynomial is 14.
Solution
To determine the degree of the given polynomial:
\[
16 w^{7} y^{4} u^{3} + 6 - 5 y^{12} - u^{11} w
\]
**Step 1: Identify the degree of each term.**
1. **\(16 w^{7} y^{4} u^{3}\)**
- Exponents: \(w^7\), \(y^4\), \(u^3\)
- Sum of exponents: \(7 + 4 + 3 = 14\)
2. **\(6\)**
- This is a constant term.
- Degree: \(0\)
3. **\(-5 y^{12}\)**
- Exponent: \(y^{12}\)
- Degree: \(12\)
4. **\(-u^{11} w\)**
- Exponents: \(u^{11}\), \(w^1\)
- Sum of exponents: \(11 + 1 = 12\)
**Step 2: Determine the highest degree among all terms.**
- The degrees of the terms are: \(14\), \(0\), \(12\), and \(12\).
- The highest degree is **14**.
**Conclusion:**
The degree of the polynomial is **14**.
Reviewed and approved by the UpStudy tutoring team
Like
error msg
Explain
Simplify this solution
The Deep Dive
The degree of a polynomial is determined by the term with the highest total degree when you sum the exponents of the variables in each term. In the polynomial \( 16 w^{7} y^{4} u^{3}+6-5 y^{12}-u^{11} w \), we have: 1. The term \( 16 w^{7} y^{4} u^{3} \) has a degree of \( 7 + 4 + 3 = 14 \). 2. The constant term \( 6 \) has a degree of \( 0\). 3. The term \( -5 y^{12} \) has a degree of \( 12 \). 4. The term \( -u^{11} w \) has a degree of \( 11 + 1 = 12 \). The highest degree among these terms is \( 14 \). Thus, the degree of the polynomial is \( 14 \).