Question
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Give the degree of the polynomial. \[ 16 w^{7} y^{4} u^{3}+6-5 y^{12}-u^{11} w \]

Ask by Ingram Matthews. in the United States
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The degree of the polynomial is 14.

Solution

To determine the degree of the given polynomial: \[ 16 w^{7} y^{4} u^{3} + 6 - 5 y^{12} - u^{11} w \] **Step 1: Identify the degree of each term.** 1. **\(16 w^{7} y^{4} u^{3}\)** - Exponents: \(w^7\), \(y^4\), \(u^3\) - Sum of exponents: \(7 + 4 + 3 = 14\) 2. **\(6\)** - This is a constant term. - Degree: \(0\) 3. **\(-5 y^{12}\)** - Exponent: \(y^{12}\) - Degree: \(12\) 4. **\(-u^{11} w\)** - Exponents: \(u^{11}\), \(w^1\) - Sum of exponents: \(11 + 1 = 12\) **Step 2: Determine the highest degree among all terms.** - The degrees of the terms are: \(14\), \(0\), \(12\), and \(12\). - The highest degree is **14**. **Conclusion:** The degree of the polynomial is **14**.

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The Deep Dive

The degree of a polynomial is determined by the term with the highest total degree when you sum the exponents of the variables in each term. In the polynomial \( 16 w^{7} y^{4} u^{3}+6-5 y^{12}-u^{11} w \), we have: 1. The term \( 16 w^{7} y^{4} u^{3} \) has a degree of \( 7 + 4 + 3 = 14 \). 2. The constant term \( 6 \) has a degree of \( 0\). 3. The term \( -5 y^{12} \) has a degree of \( 12 \). 4. The term \( -u^{11} w \) has a degree of \( 11 + 1 = 12 \). The highest degree among these terms is \( 14 \). Thus, the degree of the polynomial is \( 14 \).

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