Using the following equations, find \( f(g(x)) \) : \( f(x)=x^{2} \) \( g(x)=x-1 \) \( \left.f(g(x))=[?] x^{2}+\square x+\square\right] \)
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To find \( f(g(x)) \), we start by substituting \( g(x) \) into \( f(x) \). Given that \( g(x) = x - 1 \), we need to evaluate \( f(g(x)) = f(x - 1) \). Now, applying the function \( f(x) = x^{2} \): \[ f(g(x)) = f(x - 1) = (x - 1)^{2} \] Next, we expand \( (x - 1)^{2} \): \[ (x - 1)^{2} = x^{2} - 2x + 1 \] Thus, we can express \( f(g(x)) \) in the required form: \[ f(g(x)) = x^{2} - 2x + 1 \] Therefore, we have: \[ \left.f(g(x))=[x^{2}-2x+1\right] \] So, the final values for the boxes are -2 and 1 respectively.