Question
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4) \( |4-3 y|=12 \)

Ask by Hodgson Hodges. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\( y = -\frac{8}{3} \) or \( y = \frac{16}{3} \)

Solution

To solve the absolute value equation: \[ |4 - 3y| = 12 \] we need to consider the definition of absolute value. The absolute value of an expression equals a positive number or zero. Therefore, the equation \( |A| = B \) implies: \[ A = B \quad \text{or} \quad A = -B \] Applying this to the given equation: \[ |4 - 3y| = 12 \] leads to two separate equations: 1. **First Case: \( 4 - 3y = 12 \)** \[ \begin{align*} 4 - 3y &= 12 \\ -3y &= 12 - 4 \\ -3y &= 8 \\ y &= \frac{8}{-3} \\ y &= -\frac{8}{3} \end{align*} \] 2. **Second Case: \( 4 - 3y = -12 \)** \[ \begin{align*} 4 - 3y &= -12 \\ -3y &= -12 - 4 \\ -3y &= -16 \\ y &= \frac{-16}{-3} \\ y &= \frac{16}{3} \end{align*} \] **Solutions:** \[ y = -\frac{8}{3} \quad \text{or} \quad y = \frac{16}{3} \] These are the two values of \( y \) that satisfy the original absolute value equation.

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To solve the equation \( |4 - 3y| = 12 \), we need to consider the two scenarios that arise from the absolute value: 1. \( 4 - 3y = 12 \) 2. \( 4 - 3y = -12 \) For the first equation, \( 4 - 3y = 12 \): - Subtract 4 from both sides: \[ -3y = 8 \] - Divide by -3: \[ y = -\frac{8}{3} \] For the second equation, \( 4 - 3y = -12 \): - Subtract 4 from both sides: \[ -3y = -16 \] - Divide by -3: \[ y = \frac{16}{3} \] Thus, the solutions to the equation \( |4 - 3y| = 12 \) are \( y = -\frac{8}{3} \) and \( y = \frac{16}{3} \).

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