Id the solution of the system of equations. \[ \begin{array}{r}4 x+3 y=-14 \\ 8 x+10 y=-36\end{array} \]

To solve the system of equations, we can first simplify the second equation. Notice that the second equation can be divided by 2, giving us: \[ 4x + 5y = -18 \] Now we have the system: 1. \( 4x + 3y = -14 \) 2. \( 4x + 5y = -18 \) Next, we can subtract the first equation from the second: \[ (4x + 5y) - (4x + 3y) = -18 - (-14) \] This simplifies to: \[ 2y = -4 \] From which we can solve for \( y \): \[ y = -2 \] Now, substitute \( y = -2 \) back into the first equation to find \( x \): \[ 4x + 3(-2) = -14 \] \[ 4x - 6 = -14 \] \[ 4x = -8 \] \[ x = -2 \] Thus, the solution to the system of equations is: \[ (x, y) = (-2, -2) \]