Id the solution of the system of equations. $$ \begin{array}{r}4 x+3 y=-14 \ 8 x+10 y=-36\end{array} $$

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Solve the system of equations $$ 4x+3y=-14;8x+10y=-36 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}4x+3y=-14\8x+10y=-36\end{array}ight.$$
- step1: Solve the equation:
  $$\left\{ \begin{array}{l}x=-\frac{14+3y}{4}\8x+10y=-36\end{array}ight.$$
- step2: Substitute the value of $$x:$$
  $$8\left(-\frac{14+3y}{4}ight)+10y=-36$$
- step3: Simplify:
  $$-28+4y=-36$$
- step4: Move the constant to the right side:
  $$4y=-36+28$$
- step5: Add the numbers:
  $$4y=-8$$
- step6: Divide both sides:
  $$\frac{4y}{4}=\frac{-8}{4}$$
- step7: Divide the numbers:
  $$y=-2$$
- step8: Substitute the value of $$y:$$
  $$x=-\frac{14+3\left(-2ight)}{4}$$
- step9: Simplify:
  $$x=-2$$
- step10: Calculate:
  $$\left\{ \begin{array}{l}x=-2\y=-2\end{array}ight.$$
- step11: Check the solution:
  $$\left\{ \begin{array}{l}x=-2\y=-2\end{array}ight.$$
- step12: Rewrite:
  $$\left(x,yight) = \left(-2,-2ight)$$
La solución del sistema de ecuaciones es $$ (x,y) = (-2,-2) $$.
La solución es $$ x = -2 $$ y $$ y = -2 $$.

Id the solution of the system of equations.

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