Question

(2) \( 3 x^{4}-3 x^{2}-27 x^{2}+27 \) \( =\left(3 x^{4}+27\right)\left(-3 x^{2}-27 x^{2}\right)=\left(3 x^{4}\right. \) \( =3\left(x^{4}+9\right)-3 x^{2}(1+9)=3 x^{2}(6 \) \( = \)

Ask by Cross Graham. in South Africa
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The expression simplifies to \(3(x - 1)(x + 1)(x - 3)(x + 3)\).

Solution

Let's simplify and factor the given polynomial step by step. **Given Expression:** \[ 3x^{4} - 3x^{2} - 27x^{2} + 27 \] 1. **Combine Like Terms:** \[ -3x^{2} - 27x^{2} = -30x^{2} \] So, the expression becomes: \[ 3x^{4} - 30x^{2} + 27 \] 2. **Factor Out the Greatest Common Factor (GCF):** The GCF of the terms is **3**. \[ 3x^{4} - 30x^{2} + 27 = 3(x^{4} - 10x^{2} + 9) \] 3. **Factor the Quartic Polynomial:** Notice that \(x^{4} - 10x^{2} + 9\) is a biquadratic equation. Let’s set \(y = x^{2}\): \[ y^{2} - 10y + 9 \] Factor this quadratic: \[ y^{2} - 10y + 9 = (y - 1)(y - 9) \] Substitute back \(y = x^{2}\): \[ (x^{2} - 1)(x^{2} - 9) \] 4. **Factor Further Using Difference of Squares:** Both \(x^{2} - 1\) and \(x^{2} - 9\) are difference of squares and can be factored further: \[ x^{2} - 1 = (x - 1)(x + 1) \] \[ x^{2} - 9 = (x - 3)(x + 3) \] 5. **Combine All Factors:** Putting it all together: \[ 3(x - 1)(x + 1)(x - 3)(x + 3) \] **Final Factored Form:** \[ 3(x - 1)(x + 1)(x - 3)(x + 3) \]

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Beyond the Answer

To simplify the expression \( 3x^4 - 30x^2 + 27 \), you can start by factoring out the common factors. The expression can be rewritten as \( 3(x^4 - 10x^2 + 9) \). Next, notice that \( x^4 - 10x^2 + 9 \) can be treated as a quadratic in terms of \( y = x^2 \), leading to the factoring of \( (y - 1)(y - 9) \)—or in terms of \( x^2 \), \( (x^2 - 1)(x^2 - 9) \). Now, you can break this down further into two more factors: \( (x - 1)(x + 1)(x - 3)(x + 3) \). So, ultimately your simplified expression is: \[ 3(x-1)(x+1)(x-3)(x+3) \]. Perfect for finding roots or analyzing the graph! For fun, did you know that factoring polynomials like this has been around for centuries? Ancient Babylonian mathematicians were solving quadratic equations well before the time of algebra as we know it today! They developed early techniques for manipulations similar to factoring, demonstrating a keen understanding of numbers long before modern symbol notation. And here's a practical tip: when you have a polynomial to factor, always look for a greatest common factor first—this can simplify your work significantly! Also, common mistakes include misidentifying terms when rearranging or failing to account for signs, which can lead to incorrect factoring. Always double-check your work by expanding the factored form!

Related Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy