Solve the equation \( 20 x^{2}-7 x-6=0 \) Answer: \( x=\square \)
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To solve the equation \( 20 x^{2}-7 x-6=0 \), we can use the quadratic formula, which is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 20 \), \( b = -7 \), and \( c = -6 \). Calculating the discriminant: \[ b^2 - 4ac = (-7)^2 - 4 \cdot 20 \cdot (-6) = 49 + 480 = 529 \] Now, substituting back into the quadratic formula: \[ x = \frac{-(-7) \pm \sqrt{529}}{2 \cdot 20} = \frac{7 \pm 23}{40} \] This gives us two possible solutions: 1. \( x = \frac{30}{40} = \frac{3}{4} \) 2. \( x = \frac{-16}{40} = -\frac{2}{5} \) Thus, the solutions are: \( x = \frac{3}{4} \) or \( x = -\frac{2}{5} \) Answer: \( x=\frac{3}{4}, -\frac{2}{5} \)