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Find the number of ways to arrange the letters in CANADIAN.

Ask by Cook Haynes. in the United States
Jan 23,2025

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Answer

There are 3,360 distinct ways to arrange the letters in "CANADIAN."

Solution

To determine the number of distinct ways to arrange the letters in the word **CANADIAN**, follow these steps: 1. **Count the Total Letters**: The word "CANADIAN" has 8 letters. 2. **Identify Repeated Letters**: - **A** appears **3** times. - **N** appears **2** times. - The letters **C**, **D**, and **I** each appear **once**. 3. **Use the Formula for Permutations with Repeats**: The formula to calculate the number of distinct arrangements is: \[ \frac{n!}{n_1! \times n_2! \times \dots \times n_k!} \] Where: - \( n \) is the total number of letters. - \( n_1, n_2, \dots, n_k \) are the frequencies of the repeated letters. 4. **Apply the Values**: \[ \frac{8!}{3! \times 2!} = \frac{40320}{6 \times 2} = \frac{40320}{12} = 3360 \] **Therefore, there are 3,360 distinct ways to arrange the letters in "CANADIAN".** Answer: 3,360 distinct arrangements are possible.

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To find the number of ways to arrange the letters in "CANADIAN," we start by recognizing that this word consists of 8 letters, where certain letters repeat. The breakdown is: - C: 1 - A: 2 - N: 2 - D: 1 - I: 1 The formula for calculating the number of arrangements of letters where some letters are repeated is given by: \[ \text{Number of arrangements} = \frac{n!}{p_1! \times p_2! \times \ldots \times p_k!} \] where \( n \) is the total number of letters, and \( p_1, p_2, \ldots, p_k \) are the frequencies of the repeated letters. For "CANADIAN": - Total letters (n) = 8 - Frequencies: A occurs 2 times, N occurs 2 times So, we compute: \[ \text{Number of arrangements} = \frac{8!}{2! \times 2!} \] First, we calculate \( 8! \): \[ 8! = 40320 \] Next, calculate \( 2! \): \[ 2! = 2 \] Now plug these into the formula: \[ \text{Number of arrangements} = \frac{40320}{2 \times 2} = \frac{40320}{4} = 10080 \] Thus, the number of ways to arrange the letters in "CANADIAN" is **10,080**.

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