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Analyze the effect on the domain of \( f(x)=x^{3} \), when \( f(x) \) is replaced by \( f(b x) \) with \( b<0 \). (1 point) The domain remains all real numbers. The domain changes to zero. The domain changes to all negative real numbers. The domain remains all positive real numbers.

Ask by Barnett Lindsey. in the United States
Jan 23,2025

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Answer

The domain remains all real numbers.

Solution

When you replace \( f(x) = x^3 \) with \( f(bx) \) where \( b < 0 \), the function becomes: \[ f(bx) = (bx)^3 = b^3 x^3 \] The domain of the original function \( f(x) = x^3 \) is all real numbers (\( \mathbb{R} \)). Replacing \( x \) with \( bx \) does not impose any new restrictions on \( x \). The cube function is defined for all real numbers, regardless of the scaling factor \( b \), even if \( b \) is negative. **Answer:** The domain remains all real numbers.

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The Deep Dive

The function \( f(x) = x^3 \) has a domain of all real numbers, meaning you can input any real number into the function. When we replace \( f(x) \) with \( f(bx) \) where \( b < 0 \), we have \( f(bx) = (bx)^3 = b^3 x^3 \). Since \( b \) is negative, \( bx \) can still take on any real number value; thus, the domain of \( f(bx) \) remains all real numbers. So, the correct answer is: The domain remains all real numbers.

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