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Exercises What is the value of the discriminant and what is the number of real solutions for each equation? \( \begin{array}{lll}\text { 7. } x^{2}+x-42=0 & \text { 8. }-x^{2}+13 x-40=0 & \text { 9. } x^{2}+2 x+5=0 \\ \begin{array}{lll}\text { 10. } x^{2}=18 x-81 & \text { 11. }-x^{2}+7 x+44=0 & \text { 12. } \frac{1}{4} x^{2}-5 x+25=0\end{array} \\ \begin{array}{lll}\text { 13. } 2 x^{2}+7=5 x & \text { 14. } 4 x^{2}+25 x=21 & \text { 17. } \frac{1}{2} x^{2}+2 x+3=0\end{array} & \text { 18. } \frac{1}{6} x^{2}=2 x+18\end{array} \) Copyright © by Pearson Education, Inc., or its affiliates. All Rights Reserved.

Ask by Burns Simpson. in the United States
Jan 24,2025

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Here are the discriminants and the number of real solutions for each equation: 1. **7. \( x^{2} + x - 42 = 0 \)** - Discriminant: 169 - Real Solutions: 2 2. **8. \( -x^{2} + 13x - 40 = 0 \)** - Discriminant: 9 - Real Solutions: 2 3. **9. \( x^{2} + 2x + 5 = 0 \)** - Discriminant: -16 - Real Solutions: 0 4. **10. \( x^{2} - 18x + 81 = 0 \)** - Discriminant: 0 - Real Solutions: 1 5. **11. \( -x^{2} + 7x + 44 = 0 \)** - Discriminant: 225 - Real Solutions: 2 6. **12. \( \frac{1}{4}x^{2} - 5x + 25 = 0 \)** - Discriminant: 0 - Real Solutions: 1 7. **13. \( 2x^{2} - 5x + 7 = 0 \)** - Discriminant: -31 - Real Solutions: 0 8. **14. \( 4x^{2} + 25x - 21 = 0 \)** - Discriminant: 961 - Real Solutions: 2 9. **17. \( \frac{1}{2}x^{2} + 2x + 3 = 0 \)** - Discriminant: -2 - Real Solutions: 0 10. **18. \( x^{2} - 12x - 108 = 0 \)** - Discriminant: 576 - Real Solutions: 2

Solution

Sure, let's analyze each of the given quadratic equations to determine their discriminants and the number of real solutions they possess. The discriminant \( D \) of a quadratic equation \( ax^2 + bx + c = 0 \) is calculated using the formula: \[ D = b^2 - 4ac \] Based on the value of \( D \): - If \( D > 0 \): **Two distinct real solutions** - If \( D = 0 \): **One real solution (a repeated root)** - If \( D < 0 \): **No real solutions (two complex solutions)** Here's the breakdown for each equation: --- ### **7. \( x^{2} + x - 42 = 0 \)** - **Coefficients:** \( a = 1 \), \( b = 1 \), \( c = -42 \) - **Discriminant:** \[ D = 1^2 - 4(1)(-42) = 1 + 168 = 169 \] - **Number of Real Solutions:** **2** (since \( D = 169 > 0 \)) --- ### **8. \( -x^{2} + 13x - 40 = 0 \)** - **Coefficients:** \( a = -1 \), \( b = 13 \), \( c = -40 \) - **Discriminant:** \[ D = 13^2 - 4(-1)(-40) = 169 - 160 = 9 \] - **Number of Real Solutions:** **2** (since \( D = 9 > 0 \)) --- ### **9. \( x^{2} + 2x + 5 = 0 \)** - **Coefficients:** \( a = 1 \), \( b = 2 \), \( c = 5 \) - **Discriminant:** \[ D = 2^2 - 4(1)(5) = 4 - 20 = -16 \] - **Number of Real Solutions:** **No real solutions** (since \( D = -16 < 0 \)) --- ### **10. \( x^{2} = 18x - 81 \)** - **Rearranged Equation:** \( x^{2} - 18x + 81 = 0 \) - **Coefficients:** \( a = 1 \), \( b = -18 \), \( c = 81 \) - **Discriminant:** \[ D = (-18)^2 - 4(1)(81) = 324 - 324 = 0 \] - **Number of Real Solutions:** **1** (since \( D = 0 \)) --- ### **11. \( -x^{2} + 7x + 44 = 0 \)** - **Coefficients:** \( a = -1 \), \( b = 7 \), \( c = 44 \) - **Discriminant:** \[ D = 7^2 - 4(-1)(44) = 49 + 176 = 225 \] - **Number of Real Solutions:** **2** (since \( D = 225 > 0 \)) --- ### **12. \( \frac{1}{4}x^{2} - 5x + 25 = 0 \)** - **Coefficients:** \( a = \frac{1}{4} \), \( b = -5 \), \( c = 25 \) - **Discriminant:** \[ D = (-5)^2 - 4\left(\frac{1}{4}\right)(25) = 25 - 25 = 0 \] - **Number of Real Solutions:** **1** (since \( D = 0 \)) --- ### **13. \( 2x^{2} + 7 = 5x \)** - **Rearranged Equation:** \( 2x^{2} - 5x + 7 = 0 \) - **Coefficients:** \( a = 2 \), \( b = -5 \), \( c = 7 \) - **Discriminant:** \[ D = (-5)^2 - 4(2)(7) = 25 - 56 = -31 \] - **Number of Real Solutions:** **No real solutions** (since \( D = -31 < 0 \)) --- ### **14. \( 4x^{2} + 25x = 21 \)** - **Rearranged Equation:** \( 4x^{2} + 25x - 21 = 0 \) - **Coefficients:** \( a = 4 \), \( b = 25 \), \( c = -21 \) - **Discriminant:** \[ D = 25^2 - 4(4)(-21) = 625 + 336 = 961 \] - **Number of Real Solutions:** **2** (since \( D = 961 > 0 \)) --- ### **17. \( \frac{1}{2}x^{2} + 2x + 3 = 0 \)** - **Coefficients:** \( a = \frac{1}{2} \), \( b = 2 \), \( c = 3 \) - **Discriminant:** \[ D = 2^2 - 4\left(\frac{1}{2}\right)(3) = 4 - 6 = -2 \] - **Number of Real Solutions:** **No real solutions** (since \( D = -2 < 0 \)) --- ### **18. \( \frac{1}{6}x^{2} = 2x + 18 \)** - **Rearranged Equation:** \( \frac{1}{6}x^{2} - 2x - 18 = 0 \) - **Simplified Equation:** Multiply all terms by 6 to eliminate the fraction: \[ x^{2} - 12x - 108 = 0 \] - **Coefficients:** \( a = 1 \), \( b = -12 \), \( c = -108 \) - **Discriminant:** \[ D = (-12)^2 - 4(1)(-108) = 144 + 432 = 576 \] - **Number of Real Solutions:** **2** (since \( D = 576 > 0 \)) --- **Summary Table:** | Problem | Equation | Discriminant \( D \) | Number of Real Solutions | |---------|--------------------------------|----------------------|-------------------------------| | 7 | \( x^{2} + x - 42 = 0 \) | 169 | 2 | | 8 | \( -x^{2} + 13x - 40 = 0 \) | 9 | 2 | | 9 | \( x^{2} + 2x + 5 = 0 \) | -16 | No real solutions | | 10 | \( x^{2} - 18x + 81 = 0 \) | 0 | 1 | | 11 | \( -x^{2} + 7x + 44 = 0 \) | 225 | 2 | | 12 | \( \frac{1}{4}x^{2} - 5x +25 = 0 \) | 0 | 1 | | 13 | \( 2x^{2} - 5x + 7 = 0 \) | -31 | No real solutions | | 14 | \( 4x^{2} + 25x - 21 = 0 \) | 961 | 2 | | 17 | \( \frac{1}{2}x^{2} + 2x + 3 = 0 \) | -2 | No real solutions | | 18 | \( x^{2} - 12x - 108 = 0 \) | 576 | 2 | --- If you need further explanations or assistance with solving for the actual roots, feel free to ask!

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To find the value of the discriminant and the number of real solutions for each given equation, we'll use the discriminant formula: \(D = b^2 - 4ac\). The number of real solutions can be determined as follows: if \(D > 0\), there are two real solutions; if \(D = 0\), there's one real solution; and if \(D < 0\), there are no real solutions. 1. For \(x^2 + x - 42 = 0\): - \(D = 1^2 - 4(1)(-42) = 1 + 168 = 169\) (two real solutions). 2. For \(-x^2 + 13x - 40 = 0\): - \(D = 13^2 - 4(-1)(-40) = 169 - 160 = 9\) (two real solutions). 3. For \(x^2 + 2x + 5 = 0\): - \(D = 2^2 - 4(1)(5) = 4 - 20 = -16\) (no real solutions). 4. For \(x^2 = 18x - 81\): - Rearranging gives \(x^2 - 18x + 81 = 0\), then \(D = (-18)^2 - 4(1)(81) = 324 - 324 = 0\) (one real solution). 5. For \(-x^2 + 7x + 44 = 0\): - \(D = 7^2 - 4(-1)(44) = 49 + 176 = 225\) (two real solutions). 6. For \(\frac{1}{4} x^2 - 5x + 25 = 0\): - \(D = (-5)^2 - 4(\frac{1}{4})(25) = 25 - 25 = 0\) (one real solution). 7. For \(2x^2 + 7 = 5x\): - Rearranging gives \(2x^2 - 5x + 7 = 0\), then \(D = (-5)^2 - 4(2)(7) = 25 - 56 = -31\) (no real solutions). 8. For \(4x^2 + 25x = 21\): - Rearranging gives \(4x^2 + 25x - 21 = 0\), then \(D = 25^2 - 4(4)(-21) = 625 + 336 = 961\) (two real solutions). 9. For \(\frac{1}{2}x^2 + 2x + 3 = 0\): - \(D = 2^2 - 4(\frac{1}{2})(3) = 4 - 6 = -2\) (no real solutions). 10. For \(\frac{1}{6}x^2 = 2x + 18\): - Rearranging gives \(\frac{1}{6}x^2 - 2x - 18 = 0\), then \(D = (-2)^2 - 4(\frac{1}{6})(-18) = 4 + 12 = 16\) (two real solutions). In summary, the equations yield the following solutions: 1. Two real solutions (169) 2. Two real solutions (9) 3. No real solutions (-16) 4. One real solution (0) 5. Two real solutions (225) 6. One real solution (0) 7. No real solutions (-31) 8. Two real solutions (961) 9. No real solutions (-2) 10. Two real solutions (16)

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