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TRY IT! \[ \left.\begin{array}{lr}f(x)=\left\{\begin{array}{lr}2 x^{3}-1, & x<1 \\ 3, & 1 \leq x<5 \\ |x-2|, & x \geq 5\end{array}\right. \\ f(8)=60 & f(0)=-1\end{array} \right\rvert\, f(4)= \]

Ask by Mitchell Murray. in the United States
Feb 03,2025

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Answer

\( f(4) = 3 \)

Solution

To find \( f(4) \) using the piecewise function defined as: \[ f(x) = \begin{cases} 2x^3 - 1 & \text{if } x < 1 \\ 3 & \text{if } 1 \leq x < 5 \\ |x - 2| & \text{if } x \geq 5 \end{cases} \] we need to determine which condition \( x = 4 \) falls under. 1. **Identify the interval for \( x = 4 \)**: - The first case \( 2x^3 - 1 \) applies for \( x < 1 \). - The second case \( 3 \) applies for \( 1 \leq x < 5 \). - The third case \( |x - 2| \) applies for \( x \geq 5 \). Since \( 4 \) falls within the interval \( 1 \leq x < 5 \), we use the second case. 2. **Evaluate \( f(4) \)**: - According to the second case, \( f(4) = 3 \). Thus, the final answer is: \[ f(4) = 3 \]

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Beyond the Answer

To find \( f(4) \), we start by determining which piece of the piecewise function to use for \( x = 4 \). Since \( 1 \leq 4 < 5 \), we can see that we should use the middle piece, which is \( f(x) = 3 \). Therefore, \( f(4) = 3 \). When considering function evaluations like this one, it’s always essential to clearly identify the intervals defined in a piecewise function to avoid errors. A common mistake is to overlook the boundaries, so make sure to check which interval the input lies in before making a calculation!

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