For the quadratic function $$ y = -2x^2 + 6x - 4 $$, determine the value of the y-intercept.

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To find the y-intercept of the quadratic function $$ y = -2x^2 + 6x - 4 $$, you need to determine the value of $$ y $$ when $$ x = 0 $$.

Here's how you can do it:

1. **Substitute $$ x = 0 $$ into the equation:**
   
   $$
   y = -2(0)^2 + 6(0) - 4
   $$

2. **Simplify the expression:**
   
   $$
   y = -2(0) + 0 - 4 \
   y = 0 + 0 - 4 \
   y = -4
   $$

Therefore, the y-intercept of the quadratic function is **$$-4$$**.

**Graphical Interpretation:**
On a graph, the y-intercept is the point where the graph crosses the y-axis. For this function, the point is $$(0, -4)$$.
The y-intercept of the quadratic function $$ y = -2x^2 + 6x - 4 $$ is $$-4$$.

For the quadratic function \( y = -2x^2 + 6x - 4 \), determine the value of the y-intercept.

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