For the quadratic function \( y = -2x^2 + 6x - 4 \), determine the value of the y-intercept.

To find the y-intercept of the quadratic function \( y = -2x^2 + 6x - 4 \), you need to determine the value of \( y \) when \( x = 0 \). Here's how you can do it: 1. **Substitute \( x = 0 \) into the equation:** \[ y = -2(0)^2 + 6(0) - 4 \] 2. **Simplify the expression:** \[ y = -2(0) + 0 - 4 \\ y = 0 + 0 - 4 \\ y = -4 \] Therefore, the y-intercept of the quadratic function is **\(-4\)**. **Graphical Interpretation:** On a graph, the y-intercept is the point where the graph crosses the y-axis. For this function, the point is \((0, -4)\).