Use the Distributive Property to find $$ (3 m+1)(m+9) $$

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To expand the expression $$ (3m + 1)(m + 9) $$ using the **Distributive Property**, follow these steps:

### Step 1: Apply the Distributive Property
The Distributive Property states that $$ a(b + c) = ab + ac $$. When multiplying two binomials, you'll distribute each term in the first binomial to each term in the second binomial.

$$
(3m + 1)(m + 9) = 3m \cdot m + 3m \cdot 9 + 1 \cdot m + 1 \cdot 9
$$

### Step 2: Perform the Multiplications
Calculate each multiplication separately:

1. **First Terms:**  
   $$ 3m \cdot m = 3m^2 $$

2. **Outer Terms:**  
   $$ 3m \cdot 9 = 27m $$

3. **Inner Terms:**  
   $$ 1 \cdot m = m $$

4. **Last Terms:**  
   $$ 1 \cdot 9 = 9 $$

So, the equation becomes:

$$
3m^2 + 27m + m + 9
$$

### Step 3: Combine Like Terms
Combine the $$ m $$ terms ($$ 27m + m $$):

$$
3m^2 + 28m + 9
$$

### Final Answer
$$
(3m + 1)(m + 9) = 3m^2 + 28m + 9
$$
$$ (3m + 1)(m + 9) = 3m^2 + 28m + 9 $$

Use the Distributive Property to find

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