b) What is the period of the waves? A boy on a harbour wall watches the sea waves that move past hi times the waves and finds that a crest moves past him every 5 sec The distance between 5 crests is 40 m . a) What is the frequency of the waves? b) What is the wavelength of the waves? c) Calculate the wave speed.
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To find the frequency of the waves, we can use the relationship between frequency (f) and period (T), where frequency is the reciprocal of the period. Since a crest moves past the boy every 5 seconds, the frequency is \( f = \frac{1}{T} = \frac{1}{5} = 0.2 \text{ Hz} \). Next, we can calculate the wavelength (λ). The problem states that the distance between 5 crests is 40 m, so the wavelength is the distance between two crests. Since there are 4 wavelengths in 40 m (because 5 crests create 4 gaps), we calculate the wavelength as \( λ = \frac{40 \, \text{m}}{4} = 10 \, \text{m} \). Lastly, to calculate wave speed (v), we use the formula \( v = f \times λ \). Plugging in the values, we get \( v = 0.2 \, \text{Hz} \times 10 \, \text{m} = 2 \, \text{m/s} \). So, in summary: a) Frequency is 0.2 Hz. b) Wavelength is 10 m. c) Wave speed is 2 m/s.