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Rewrite the polynomial in the form \( a x+b y+c \) and then identify the values of \( a, b \), and \( e \) \[ 1-9 y+\frac{1}{3} x \]

Ask by Watkins Herrera. in the United States
Jan 24,2025

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The polynomial \( 1 - 9y + \frac{1}{3}x \) can be rewritten as \( \frac{1}{3}x - 9y + 1 \). The coefficients are: - \( a = \frac{1}{3} \) - \( b = -9 \) - \( c = 1 \)

Solution

Certainly! Let's rewrite the given polynomial in the form \( a x + b y + c \) and then identify the values of \( a \), \( b \), and \( c \). ### Given Polynomial: \[ 1 - 9y + \frac{1}{3}x \] ### Rewriting in the Desired Form: To express the polynomial in the form \( a x + b y + c \), we can rearrange the terms as follows: \[ \frac{1}{3}x - 9y + 1 \] So, the polynomial in the form \( a x + b y + c \) is: \[ \frac{1}{3}x - 9y + 1 \] ### Identifying the Coefficients: - **\( a \)** (coefficient of \( x \)): \( \frac{1}{3} \) - **\( b \)** (coefficient of \( y \)): \( -9 \) - **\( c \)** (constant term): \( 1 \) ### Summary: \[ a = \frac{1}{3}, \quad b = -9, \quad c = 1 \]

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To rewrite the polynomial \( 1 - 9y + \frac{1}{3}x \) in the form \( ax + by + c \), we can rearrange the terms as follows: \[ \frac{1}{3}x - 9y + 1 \] In this format, we can identify the coefficients: - \( a = \frac{1}{3} \) - \( b = -9 \) - \( c = 1 \) So the values are \( a = \frac{1}{3} \), \( b = -9 \), and \( c = 1 \).

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