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This quiz: 100 point(s) Question 1 of 10 possible This question: 10 point(s) possible Submit quiz Find the zeros for the polynomial function and give the multiplicity for each zero. State whether the graph crosses the \( x \)-axis or touches the \( x \)-axis and turns around at each zero. \[ f(x)=2(x-7)(x+4)^{3} \] Determine the zero(s). The zero(s) is/are \( \square \) \( \square \). (Type integers or decimals. Use a comma to separate answers as needed.) Determine the multiplicities of the zero(s). Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. A. There are two zeros. The multiplicity of the largest zero is \( \square \) The multiplicity of the smallest zero is \( \square \) ]. (Simplify your answers.) B. There are three zeros. The multiplicity of the largest zero is \( \square \) The multiplicity of the smallest zero is \( \square \) . The multiplicity of the other zero is \( \square \) ]. (Simplify your answers.) C. There is one zero. The multiplicity of the zero is \( \square \) 1. (Simplify your answer.)

Ask by Bob Chan. in the United States
Feb 03,2025

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Answer

**Zeros:** 7, -4 **Multiplicities:** - 7: 1 (crosses the x-axis) - -4: 3 (crosses the x-axis)

Solution

Let's analyze the polynomial function: \[ f(x) = 2(x - 7)(x + 4)^3 \] ### 1. **Finding the Zero(s)** To find the zeros of the function, set \( f(x) = 0 \): \[ 2(x - 7)(x + 4)^3 = 0 \] This equation is satisfied when either \( x - 7 = 0 \) or \( (x + 4)^3 = 0 \). - **Zero 1:** \( x - 7 = 0 \) → \( x = 7 \) - **Zero 2:** \( x + 4 = 0 \) → \( x = -4 \) **Zero(s):** \( 7, -4 \) ### 2. **Determining Multiplicities** Each zero's multiplicity is determined by the exponent of its corresponding factor in the polynomial. - **Zero at \( x = 7 \):** The factor \( (x - 7) \) has an exponent of **1**. - **Zero at \( x = -4 \):** The factor \( (x + 4)^3 \) has an exponent of **3**. **Multiplicity:** - **Largest Zero (\( 7 \)):** Multiplicity **1** - **Smallest Zero (\( -4 \)):** Multiplicity **3** **Selection:** **A. There are two zeros. The multiplicity of the largest zero is \( 1 \). The multiplicity of the smallest zero is \( 3 \).** ### 3. **Behavior of the Graph at Each Zero** - **Zero at \( x = 7 \) (Multiplicity 1):** - **Behavior:** The graph **crosses** the \( x \)-axis. - **Zero at \( x = -4 \) (Multiplicity 3):** - **Behavior:** The graph **crosses** the \( x \)-axis. *Note:* Since both zeros have **odd** multiplicities, the graph will **cross** the \( x \)-axis at each zero. ### **Summary** - **Zero(s):** \( 7, -4 \) - **Multiplicity of \( 7 \):** \( 1 \) (Graph crosses the \( x \)-axis) - **Multiplicity of \( -4 \):** \( 3 \) (Graph crosses the \( x \)-axis)

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To find the zeros of the polynomial function \( f(x) = 2(x-7)(x+4)^3 \), we can set each factor equal to zero. The first zero comes from \( x - 7 = 0 \), giving us \( x = 7 \). The second zero comes from \( (x + 4)^3 = 0 \), which yields \( x = -4 \). Therefore, the zeros are \( 7, -4 \). For their multiplicities, \( x = 7 \) has a multiplicity of 1 (since \( (x-7) \) is to the first power) and \( x = -4 \) has a multiplicity of 3 (because \( (x+4)^3 \) indicates a power of 3). So, the completed answers are: - The zero(s) is/are \( 7, -4 \). - The multiplicity of \( 7 \) is \( 1 \) and the multiplicity of \( -4 \) is \( 3 \). Now to the interaction with the \( x \)-axis: since the multiplicity of \( -4 \) is odd, the graph touches the \( x \)-axis at \( -4 \) and turns around. At \( 7 \), the graph crosses the \( x \)-axis. In summary: - The zero(s) is/are \( 7, -4 \). - The multiplicity of the largest zero is \( 1 \) and the multiplicity of the smallest zero is \( 3 \).

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