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\( \frac{\text { Factorise }}{9 y-6} \) \( 2.92(y-8) \) \( 4.70+10 q \) \( 70(9+5) \) \( 6 \begin{array}{r}8-129 \\ 8(9-6)\end{array} \) \( 8.15 y-20 \) \( 15(y-5) \) \( 10.4 x(14 x y) \) \( 4 x(12) \) 12

Ask by Reeves Joseph. in South Africa
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

Here are the factored forms of the given expressions: 1. \( 9y - 6 = 3(3y - 2) \) 2. \( 2.92(y - 8) \) (already factored) 3. \( 4.70 + 10q = 0.10(47 + 100q) \) or \( 10(0.47 + q) \) 4. \( 70(9 + 5) = 70 \times 14 = 980 \) (prime factors: \( 2^2 \times 5 \times 7^2 \)) 5. \( 6(8 - 129) = -726 \) and \( 6 \times 8 \times (9 - 6) = 144 \) 6. \( 8.15y - 20 = 0.05(163y - 400) \) 7. \( 15(y - 5) \) (already factored) 8. \( 10.4x(14xy) = 145.6x^2y \) (or \( 0.8(182x^2y) \)) 9. \( 4x(12) = 48x \) (prime factors: \( 2^4 \times 3 \times x \)) 10. \( 12 = 2^2 \times 3 \) If you need further simplification or specific factoring methods, let me know!

Solution

Certainly! Let's factorize each of the given expressions step by step. --- 1. **\( 9y - 6 \)** - **Factorize the greatest common factor (GCF):** \[ 9y - 6 = 3(3y - 2) \] 2. **\( 2.92(y - 8) \)** - **Already in factored form:** \[ 2.92(y - 8) \] 3. **\( 4.70 + 10q \)** - **Factor out the GCF of 0.10:** \[ 4.70 + 10q = 0.10(47 + 100q) \] - **Alternatively, factor out 10:** \[ 4.70 + 10q = 10(0.47 + q) \] 4. **\( 70(9 + 5) \)** - **Simplify inside the parentheses:** \[ 70(9 + 5) = 70 \times 14 = 980 \] - **Prime factorization of 980:** \[ 980 = 2^2 \times 5 \times 7^2 \] 5. **\( 6 \begin{array}{r}8 - 129 \\ 8(9 - 6)\end{array} \)** - **Assuming two separate expressions:** a. **First Expression:** \[ 6(8 - 129) = 6(-121) = -726 \] b. **Second Expression:** \[ 6 \times 8 \times (9 - 6) = 6 \times 8 \times 3 = 144 \] 6. **\( 8.15y - 20 \)** - **Factor out the GCF of 0.05:** \[ 8.15y - 20 = 0.05(163y - 400) \] 7. **\( 15(y - 5) \)** - **Already in factored form:** \[ 15(y - 5) \] 8. **\( 10.4x(14xy) \)** - **Multiply the constants and combine like terms:** \[ 10.4x \times 14xy = 145.6x^2y \] - **Factor out the GCF if desired (e.g., 0.8):** \[ 145.6x^2y = 0.8(182x^2y) \] 9. **\( 4x(12) \)** - **Multiply the constants:** \[ 4x \times 12 = 48x \] - **Prime factorization of 48:** \[ 48x = 2^4 \times 3 \times x \] 10. **\( 12 \)** - **Prime factorization:** \[ 12 = 2^2 \times 3 \] --- If you need further simplification or have specific preferences for factoring (like factoring over integers, primes, etc.), feel free to let me know!

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Bonus Knowledge

To factorise \(9y - 6\), you can start by finding the greatest common factor (GCF) of the terms, which is 3. So, you can rewrite this as \(3(3y - 2)\). It’s like having a cake and cutting it into smaller slices – you’re simplifying the expression while keeping the overall 'flavor' intact! For the expression \(10.4x(14xy)\), notice how it involves both a coefficient and variables. Multiplying these together allows you to combine them into one expression: \(10.4 \cdot 14xy = 145.6xy\). This showcases the beauty of algebra – combining terms to create a neat package!

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