Question
upstudy study bank question image url

Given that \( g(x)=\frac{x-6}{x+5} \), lind each of the following. a) \( g(9) \) b) \( g(6) \) c) \( 9(-5) \) d) \( 9(-1325) \) e) \( 9(x+h) \) C. \( g(6) \) is not a real number. c) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( g(-5)= \) \( \square \) (Simplify your answer.) B. \( g(-5) \) does not exist. C. \( g(-5) \) is not a real number. d) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( g(-13.25)=\frac{7}{3} \) (Type an integer or decimal rounded to three decimal places as needed.) B. \( g(-13.25) \) does nol exist. C. \( g(-13.25) \) is not a real number. e) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( g(x+h)=\square \) (Simplify your answer.) \( \square \) B. \( g(x+h) \) does not exist. C. \( g(x+h) \) is not a real number.

Ask by Weston Lang. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

a) \( g(9) = \frac{3}{14} \) b) \( g(6) = 0 \) c) \( 9(-5) = -45 \) d) \( 9(-1325) = -11925 \) e) \( 9(x + h) = 9x + 9h \) f) \( g(-5) \) does not exist. g) \( g(-13.25) \approx 2.333 \) h) \( g(x + h) = \frac{x + h - 6}{x + h + 5} \)

Solution

Let's solve the problem step by step. ### Given Function The function is defined as: \[ g(x) = \frac{x - 6}{x + 5} \] ### Part a: Calculate \( g(9) \) To find \( g(9) \): \[ g(9) = \frac{9 - 6}{9 + 5} = \frac{3}{14} \] ### Part b: Calculate \( g(6) \) To find \( g(6) \): \[ g(6) = \frac{6 - 6}{6 + 5} = \frac{0}{11} = 0 \] ### Part c: Calculate \( 9(-5) \) Calculating \( 9(-5) \): \[ 9(-5) = -45 \] ### Part d: Calculate \( 9(-1325) \) Calculating \( 9(-1325) \): \[ 9(-1325) = -11925 \] ### Part e: Calculate \( 9(x + h) \) Calculating \( 9(x + h) \): \[ 9(x + h) = 9x + 9h \] ### Part f: Determine \( g(-5) \) To find \( g(-5) \): \[ g(-5) = \frac{-5 - 6}{-5 + 5} = \frac{-11}{0} \] Since division by zero is undefined, \( g(-5) \) does not exist. ### Part g: Determine \( g(-13.25) \) To find \( g(-13.25) \): \[ g(-13.25) = \frac{-13.25 - 6}{-13.25 + 5} = \frac{-19.25}{-8.25} \] Calculating this gives: \[ g(-13.25) = \frac{19.25}{8.25} \approx 2.333 \text{ (rounded to three decimal places)} \] ### Part h: Determine \( g(x + h) \) To find \( g(x + h) \): \[ g(x + h) = \frac{(x + h) - 6}{(x + h) + 5} = \frac{x + h - 6}{x + h + 5} = \frac{x + h - 6}{x + h + 5} \] ### Summary of Answers - a) \( g(9) = \frac{3}{14} \) - b) \( g(6) = 0 \) - c) \( 9(-5) = -45 \) - d) \( 9(-1325) = -11925 \) - e) \( 9(x + h) = 9x + 9h \) - f) \( g(-5) \) does not exist. - g) \( g(-13.25) \approx 2.333 \) - h) \( g(x + h) = \frac{x + h - 6}{x + h + 5} \)

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Extra Insights

Let's dive into the function \( g(x) = \frac{x-6}{x+5} \) and tackle each part one by one! a) To find \( g(9) \), we plug \( 9 \) into the function: \[ g(9) = \frac{9-6}{9+5} = \frac{3}{14}. \] b) For \( g(6) \): \[ g(6) = \frac{6-6}{6+5} = \frac{0}{11} = 0. \] c) To calculate \( 9(-5) \): \[ 9(-5) = -45. \] d) Calculating \( 9(-1325) \): \[ 9(-1325) = -11925. \] e) For \( 9(x+h) \): This is simply distributing \( 9 \): \[ 9(x+h) = 9x + 9h. \] Now, let’s address the statements about the non-existence or real numbers. **C.** \( g(6) \) is indeed a real number as it evaluates to \( 0 \). For \( g(-5) \), since the denominator becomes zero: - The correct answer is **B:** \( g(-5) \) does not exist. For \( g(-13.25) \): Calculating it gives: \[ g(-13.25) = \frac{-13.25 - 6}{-13.25 + 5} = \frac{-19.25}{-8.25} = \frac{19.25}{8.25} \approx 2.333. \] Hence for the options: - Correct answer is **A:** \( g(-13.25) \approx 2.333 \) (rounded to three decimal places). For \( g(x+h) \): \[ g(x+h) = \frac{(x+h)-6}{(x+h)+5} = \frac{x+h-6}{x+h+5}. \] So the correct choice would be **A:** \( g(x+h) = \frac{x+h-6}{x+h+5} \).

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy