Given that \( g(x)=\frac{x-6}{x+5} \), lind each of the following. a) \( g(9) \) b) \( g(6) \) c) \( 9(-5) \) d) \( 9(-1325) \) e) \( 9(x+h) \) C. \( g(6) \) is not a real number. c) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( g(-5)= \) \( \square \) (Simplify your answer.) B. \( g(-5) \) does not exist. C. \( g(-5) \) is not a real number. d) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( g(-13.25)=\frac{7}{3} \) (Type an integer or decimal rounded to three decimal places as needed.) B. \( g(-13.25) \) does nol exist. C. \( g(-13.25) \) is not a real number. e) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( g(x+h)=\square \) (Simplify your answer.) \( \square \) B. \( g(x+h) \) does not exist. C. \( g(x+h) \) is not a real number.
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Let's dive into the function \( g(x) = \frac{x-6}{x+5} \) and tackle each part one by one! a) To find \( g(9) \), we plug \( 9 \) into the function: \[ g(9) = \frac{9-6}{9+5} = \frac{3}{14}. \] b) For \( g(6) \): \[ g(6) = \frac{6-6}{6+5} = \frac{0}{11} = 0. \] c) To calculate \( 9(-5) \): \[ 9(-5) = -45. \] d) Calculating \( 9(-1325) \): \[ 9(-1325) = -11925. \] e) For \( 9(x+h) \): This is simply distributing \( 9 \): \[ 9(x+h) = 9x + 9h. \] Now, let’s address the statements about the non-existence or real numbers. **C.** \( g(6) \) is indeed a real number as it evaluates to \( 0 \). For \( g(-5) \), since the denominator becomes zero: - The correct answer is **B:** \( g(-5) \) does not exist. For \( g(-13.25) \): Calculating it gives: \[ g(-13.25) = \frac{-13.25 - 6}{-13.25 + 5} = \frac{-19.25}{-8.25} = \frac{19.25}{8.25} \approx 2.333. \] Hence for the options: - Correct answer is **A:** \( g(-13.25) \approx 2.333 \) (rounded to three decimal places). For \( g(x+h) \): \[ g(x+h) = \frac{(x+h)-6}{(x+h)+5} = \frac{x+h-6}{x+h+5}. \] So the correct choice would be **A:** \( g(x+h) = \frac{x+h-6}{x+h+5} \).