Solve the quadratic equation by completing the square. \[ x^{2}+18 x+71=0 \] First, choose the appropriate form and fill in the blanks with the correct nur Then, solve the equation. Simplify your answer as much as possible. If there is more than one solution, separate them with commas. Form: \( \quad(x+\square)^{2}=\square \) Solution: \( x=\square \)
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To solve the quadratic equation \( x^{2}+18 x+71=0 \) by completing the square, we first need to reformat the quadratic expression. We begin with: \[ x^2 + 18x = -71 \] Next, we take half of the coefficient of \( x \) (which is 18), square it, and add that value to both sides. Half of 18 is 9, and \( 9^2 = 81 \). We can add 81 to both sides: \[ x^2 + 18x + 81 = -71 + 81 \] This simplifies to: \[ x^2 + 18x + 81 = 10 \] Now, we can express the left side as a perfect square: \[ (x + 9)^2 = 10 \] Now we can fill in the blanks: Form: \( \quad (x + 9)^{2} = 10 \) To solve for \( x \), we take the square root of both sides: \[ x + 9 = \pm \sqrt{10} \] Now, isolating \( x \): \[ x = -9 \pm \sqrt{10} \] Thus, we have two solutions: Solution: \( x = -9 + \sqrt{10}, -9 - \sqrt{10} \)