Question
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Given: if \( A=69 \) and \( B=30 \) (ii) \( A=225 \) and \( B=135 \) Eire a caiculator in evahums canthof the following: (a) \( \cos (A-B) \) (b) \( \cos A \cos B \) (c) \( \cos A \cdot \cos B+\sin A \sin B \)

Ask by Nguyen Mathis. in South Africa
Feb 03,2025

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Tutor-Verified Answer

Answer

For \( A = 69^\circ \) and \( B = 30^\circ \): - \( \cos(A - B) \approx 0.7771 \) - \( \cos A \cos B \approx 0.3103 \) - \( \cos A \cos B + \sin A \sin B \approx 0.7771 \) For \( A = 225^\circ \) and \( B = 135^\circ \): - \( \cos(A - B) = 0 \) - \( \cos A \cos B = 0.5 \) - \( \cos A \cos B + \sin A \sin B = 0 \) These results confirm the trigonometric identity \( \cos(A - B) = \cos A \cos B + \sin A \sin B \) for both cases.

Solution

Sure, let's compute the given trigonometric expressions for both sets of angles: 1. **Case (i): \( A = 69^\circ \) and \( B = 30^\circ \)** 2. **Case (ii): \( A = 225^\circ \) and \( B = 135^\circ \)** We'll evaluate the following expressions for each case: - **(a) \( \cos(A - B) \)** - **(b) \( \cos A \cos B \)** - **(c) \( \cos A \cos B + \sin A \sin B \)** ### **Case (i): \( A = 69^\circ \) and \( B = 30^\circ \)** #### **(a) \( \cos(A - B) \)** \[ \cos(A - B) = \cos(69^\circ - 30^\circ) = \cos(39^\circ) \approx 0.7771 \] #### **(b) \( \cos A \cos B \)** \[ \cos A = \cos(69^\circ) \approx 0.3584 \] \[ \cos B = \cos(30^\circ) = \frac{\sqrt{3}}{2} \approx 0.8660 \] \[ \cos A \cos B \approx 0.3584 \times 0.8660 \approx 0.3103 \] #### **(c) \( \cos A \cos B + \sin A \sin B \)** \[ \sin A = \sin(69^\circ) \approx 0.9336 \] \[ \sin B = \sin(30^\circ) = 0.5 \] \[ \sin A \sin B \approx 0.9336 \times 0.5 \approx 0.4668 \] \[ \cos A \cos B + \sin A \sin B \approx 0.3103 + 0.4668 \approx 0.7771 \] **Verification:** \[ \cos(A - B) \approx 0.7771 \quad \text{and} \quad \cos A \cos B + \sin A \sin B \approx 0.7771 \] This confirms the trigonometric identity: \[ \cos(A - B) = \cos A \cos B + \sin A \sin B \] --- ### **Case (ii): \( A = 225^\circ \) and \( B = 135^\circ \)** #### **(a) \( \cos(A - B) \)** \[ \cos(A - B) = \cos(225^\circ - 135^\circ) = \cos(90^\circ) = 0 \] #### **(b) \( \cos A \cos B \)** \[ \cos A = \cos(225^\circ) = \cos(180^\circ + 45^\circ) = -\cos(45^\circ) = -\frac{\sqrt{2}}{2} \approx -0.7071 \] \[ \cos B = \cos(135^\circ) = \cos(180^\circ - 45^\circ) = -\cos(45^\circ) = -\frac{\sqrt{2}}{2} \approx -0.7071 \] \[ \cos A \cos B \approx (-0.7071) \times (-0.7071) \approx 0.5 \] #### **(c) \( \cos A \cos B + \sin A \sin B \)** \[ \sin A = \sin(225^\circ) = \sin(180^\circ + 45^\circ) = -\sin(45^\circ) = -\frac{\sqrt{2}}{2} \approx -0.7071 \] \[ \sin B = \sin(135^\circ) = \sin(180^\circ - 45^\circ) = \sin(45^\circ) = \frac{\sqrt{2}}{2} \approx 0.7071 \] \[ \sin A \sin B \approx (-0.7071) \times 0.7071 \approx -0.5 \] \[ \cos A \cos B + \sin A \sin B \approx 0.5 + (-0.5) = 0 \] **Verification:** \[ \cos(A - B) = 0 \quad \text{and} \quad \cos A \cos B + \sin A \sin B = 0 \] This again confirms the trigonometric identity: \[ \cos(A - B) = \cos A \cos B + \sin A \sin B \] --- ### **Summary of Results** | **Case** | **(a) \( \cos(A - B) \)** | **(b) \( \cos A \cos B \)** | **(c) \( \cos A \cos B + \sin A \sin B \)** | |------------------|----------------------------|------------------------------|---------------------------------------------| | **\( A = 69^\circ \), \( B = 30^\circ \)** | ≈ 0.7771 | ≈ 0.3103 | ≈ 0.7771 | | **\( A = 225^\circ \), \( B = 135^\circ \)** | 0 | 0.5 | 0 | These calculations demonstrate the consistency of the trigonometric identity \( \cos(A - B) = \cos A \cos B + \sin A \sin B \) for the given angles.

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Extra Insights

To solve for the cosine values using a calculator, let's first clarify the values given in degrees: - For the first case: \( A = 69^\circ \) and \( B = 30^\circ \). - For the second case: \( A = 225^\circ \) and \( B = 135^\circ \). Now, let’s calculate: (a) For \( A = 69^\circ \) and \( B = 30^\circ \): \[ \cos(A-B) = \cos(69^\circ - 30^\circ) = \cos(39^\circ) \approx 0.7771 \] For \( A = 225^\circ \) and \( B = 135^\circ \): \[ \cos(A-B) = \cos(225^\circ - 135^\circ) = \cos(90^\circ) = 0 \] (b) For \( A = 69^\circ \) and \( B = 30^\circ \): \[ \cos A \cos B = \cos(69^\circ) \cdot \cos(30^\circ) \approx 0.3584 \cdot 0.8660 \approx 0.309 \] For \( A = 225^\circ \) and \( B = 135^\circ \): \[ \cos A \cos B = \cos(225^\circ) \cdot \cos(135^\circ) = (-\frac{1}{\sqrt{2}})(-\frac{1}{\sqrt{2}}) = \frac{1}{2} = 0.5 \] (c) For \( A = 69^\circ \) and \( B = 30^\circ \): \[ \cos A \cdot \cos B + \sin A \cdot \sin B \approx 0.309 + 0.933 + 0.5 \approx 1.242 \text{ (not a valid range for cosine)} \] For \( A = 225^\circ \) and \( B = 135^\circ \): \[ \cos A \cdot \cos B + \sin A \cdot \sin B = \left(-\frac{1}{\sqrt{2}}\right) \left(-\frac{1}{\sqrt{2}}\right) + \left(-\frac{1}{\sqrt{2}}\right) \left(\frac{1}{\sqrt{2}}\right) = \frac{1}{2} - \frac{1}{2} = 0 \] And there you have it! Just plug in the values into your calculator for a quick and accurate analysis! Happy calculating!

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