Question
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You invest \( \$ 800 \) at an annual rate of \( 8 \% \) for 12 years. How much more interest would you earn with compound interest than with simple interest for (a) the whole 12 years; and (b) in just year 7 by itself?

Ask by Welch Little. in the United States
Jan 22,2025

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Answer

Over 12 years, you earn \$445 more with compound interest. In year 7, you earn \$38 more with compound interest.

Solution

To determine the difference in interest earned using **compound interest** versus **simple interest**, we'll analyze both scenarios: - **Principal (P):** \$800 - **Annual Interest Rate (r):** 8% or 0.08 - **Time (t):** 12 years ### (a) Difference Over the Whole 12 Years 1. **Simple Interest (Iβ‚›):** \[ Iβ‚› = P \times r \times t = 800 \times 0.08 \times 12 = \$768 \] 2. **Compound Interest (I𝚌):** - **Amount (A):** \[ A = P \times (1 + r)^t = 800 \times (1.08)^{12} \] - Calculate \((1.08)^{12}\): \[ (1.08)^{12} \approx 2.5161 \] - **Total Amount (A):** \[ A \approx 800 \times 2.5161 = \$2,012.88 \] - **Interest Earned (I𝚌):** \[ I𝚌 = A - P = 2,012.88 - 800 = \$1,212.88 \] 3. **Difference (I𝚌 - Iβ‚›):** \[ 1,212.88 - 768 = \$444.88 \] **Rounded to the nearest dollar:** **\$445** more with compound interest over 12 years. --- ### (b) Difference in Just Year 7 1. **Simple Interest for Year 7 (Iₛ₇):** \[ Iₛ₇ = P \times r = 800 \times 0.08 = \$64 \] 2. **Compound Interest for Year 7 (IπšŒβ‚‡):** - **Amount at Beginning of Year 7:** \[ A₆ = P \times (1 + r)^6 = 800 \times (1.08)^6 \approx 800 \times 1.5869 = \$1,269.52 \] - **Interest Earned in Year 7:** \[ IπšŒβ‚‡ = A₆ \times r = 1,269.52 \times 0.08 \approx \$101.56 \] 3. **Difference (IπšŒβ‚‡ - Iₛ₇):** \[ 101.56 - 64 = \$37.56 \] **Rounded to the nearest dollar:** **\$38** more with compound interest in year 7. --- ### **Summary** - **(a)** Over **12 years**, compound interest earns **\$445** more than simple interest. - **(b)** In **year 7**, compound interest earns **\$38** more than simple interest.

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The Deep Dive

To find out how much more interest you would earn with compound interest compared to simple interest, let’s calculate both types of interest. 1. **Simple Interest**: The formula for simple interest is \( I = P \cdot r \cdot t \), where \( P \) is the principal amount, \( r \) is the annual interest rate, and \( t \) is the time in years. \[ I = 800 \cdot 0.08 \cdot 12 = 800 \cdot 0.96 = 768 \] So, the total simple interest earned over 12 years is \( \$ 768 \). 2. **Compound Interest**: The formula for compound interest is \( A = P(1 + r)^t \), where \( A \) is the amount of money accumulated after n years, including interest. \[ A = 800(1 + 0.08)^{12} \approx 800(2.51817) \approx 2014.54 \] The total compound interest earned is \( A - P = 2014.54 - 800 \approx 1214.54 \). Now, let's calculate the difference in interest earned: \[ \text{Difference} = 1214.54 - 768 = 446.54 \] So, you would earn **about \( \$ 446.54 \)** more with compound interest than with simple interest over the entire 12 years. **(b)** To find the interest earned in just year 7 with compound interest, we can calculate the total amount at the end of year 6, then find the amount at the end of year 7, and subtract the two: \[ A_{6} = 800(1 + 0.08)^{6} \approx 800(1.58687) \approx 1269.50 \] \[ A_{7} = 800(1 + 0.08)^{7} \approx 800(1.71382) \approx 1371.06 \] The interest earned during year 7 is: \[ I_{7} = A_{7} - A_{6} = 1371.06 - 1269.50 \approx 101.56 \] For simple interest during year 7, it is the same as each year: \[ I_{7, \text{simple}} = 800 \cdot 0.08 = 64 \] The difference in interest for year 7: \[ \text{Difference}_{7} = 101.56 - 64 \approx 37.56 \] Thus, you would earn **about \( \$ 37.56 \)** more with compound interest than with simple interest in just year 7.

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