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(5) \( 2 n+5>1 \) and \( 3 n+4>7 \) 6) \( -4 u+9>1 \) and \( 7 u-13 \leq-6 \) (7) \( 32 \leq 3 x+20 \) or \( 17>1-8 x \) 8) \( -2 k+8<14 \) or \( 3 k+1<1 \) 9) \( 5(w+4) \geqslant 5 \) and \( 2(w+4)<12 \)

Ask by Morrison Hodges. in the United States
Feb 03,2025

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Answer

**Solutions:** 1. **Problem 5:** \( n > 1 \) 2. **Problem 6:** \( u \leq 1 \) 3. **Problem 7:** \( x > -2 \) 4. **Problem 8:** All real numbers 5. **Problem 9:** \( -3 \leq w < 2 \)

Solution

Sure, let's solve each of the given inequalities step by step. --- ### **5. \( 2n + 5 > 1 \) and \( 3n + 4 > 7 \)** **First Inequality:** \[ 2n + 5 > 1 \\ 2n > 1 - 5 \\ 2n > -4 \\ n > -2 \] **Second Inequality:** \[ 3n + 4 > 7 \\ 3n > 7 - 4 \\ 3n > 3 \\ n > 1 \] **Combined Solution (AND condition):** \[ n > 1 \] *Both conditions must be satisfied, so the solution is \( n > 1 \).* --- ### **6. \( -4u + 9 > 1 \) and \( 7u - 13 \leq -6 \)** **First Inequality:** \[ -4u + 9 > 1 \\ -4u > 1 - 9 \\ -4u > -8 \\ u < 2 \quad \text{(divide by -4 and reverse the inequality)} \] **Second Inequality:** \[ 7u - 13 \leq -6 \\ 7u \leq -6 + 13 \\ 7u \leq 7 \\ u \leq 1 \] **Combined Solution (AND condition):** \[ u \leq 1 \] *Both conditions must be satisfied, so the solution is \( u \leq 1 \).* --- ### **7. \( 32 \leq 3x + 20 \) or \( 17 > 1 - 8x \)** **First Inequality:** \[ 32 \leq 3x + 20 \\ 3x \geq 32 - 20 \\ 3x \geq 12 \\ x \geq 4 \] **Second Inequality:** \[ 17 > 1 - 8x \\ 17 - 1 > -8x \\ 16 > -8x \\ x > -2 \quad \text{(divide by -8 and reverse the inequality)} \] **Combined Solution (OR condition):** \[ x \geq 4 \quad \text{or} \quad x > -2 \] *Simplifying, this covers all real numbers greater than \(-2\). So, the solution is \( x > -2 \).* --- ### **8. \( -2k + 8 < 14 \) or \( 3k + 1 < 1 \)** **First Inequality:** \[ -2k + 8 < 14 \\ -2k < 14 - 8 \\ -2k < 6 \\ k > -3 \quad \text{(divide by -2 and reverse the inequality)} \] **Second Inequality:** \[ 3k + 1 < 1 \\ 3k < 1 - 1 \\ 3k < 0 \\ k < 0 \] **Combined Solution (OR condition):** \[ k > -3 \quad \text{or} \quad k < 0 \] *Since \( k > -3 \) already includes \( k < 0 \) and \( k \geq 0 \), the combined solution covers all real numbers. Therefore, **all real numbers** are solutions.* --- ### **9. \( 5(w + 4) \geq 5 \) and \( 2(w + 4) < 12 \)** **First Inequality:** \[ 5(w + 4) \geq 5 \\ w + 4 \geq 1 \\ w \geq -3 \] **Second Inequality:** \[ 2(w + 4) < 12 \\ w + 4 < 6 \\ w < 2 \] **Combined Solution (AND condition):** \[ -3 \leq w < 2 \] *Both conditions must be satisfied, so the solution is \( -3 \leq w < 2 \).* --- ### **Summary of Solutions:** 1. **Problem 5:** \( n > 1 \) 2. **Problem 6:** \( u \leq 1 \) 3. **Problem 7:** \( x > -2 \) 4. **Problem 8:** All real numbers (any real number satisfies at least one inequality) 5. **Problem 9:** \( -3 \leq w < 2 \) --- If you have any further questions or need additional explanations, feel free to ask!

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Beyond the Answer

To solve these inequalities and systems, let's break them down step-by-step! You want to isolate the variable by performing operations to both sides. Remember, if you multiply or divide by a negative number, you must flip the inequality sign! So let's take those inequalities one by one and have some fun with math! Now, if you find yourself stuck, don’t fret! Drawing a number line can help visualize where the solutions lie, especially when dealing with compound inequalities. And remember, when combining inequalities with 'and,' the solution set is the intersection, while for 'or,' it covers the union of possible solutions, so keep an eye on those symbols!

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