In the product $$ (3 x-2)(x+4)=3 x^{2}+10 x-8 $$, the polynomials $$ (3 x-2) $$ and $$ (x+4) $$ are called $$ \square $$ of the polynomial $$ 3 x^{2}+10 x-8 $$

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In the context of polynomials, the terms $$ (3x - 2) $$ and $$ (x + 4) $$ are referred to as the **factors** of the polynomial $$ 3x^2 + 10x - 8 $$.

To clarify, when you multiply the factors $$ (3x - 2) $$ and $$ (x + 4) $$, you obtain the polynomial $$ 3x^2 + 10x - 8 $$. Thus, the complete statement would be:

In the product $$ (3x - 2)(x + 4) = 3x^2 + 10x - 8 $$, the polynomials $$ (3x - 2) $$ and $$ (x + 4) $$ are called **factors** of the polynomial $$ 3x^2 + 10x - 8 $$.
In the product $$ (3x - 2)(x + 4) = 3x^2 + 10x - 8 $$, the polynomials $$ (3x - 2) $$ and $$ (x + 4) $$ are called **factors** of the polynomial $$ 3x^2 + 10x - 8 $$.

In the product , the polynomials and are called of the polynomial

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