2. \( \frac{71^{2}-23^{2}+94 \cdot 42}{62^{2}-32^{2}} \) ni hisoblang A) \( \frac{5}{6} \).B) \( \frac{1}{3} \).(C) 3 . D) 4 .
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Bani avval, ifodani soddalashtiramiz: \( \frac{71^{2}-23^{2}+94 \cdot 42}{62^{2}-32^{2}} \). Denglama: \( a^2 - b^2 = (a-b)(a+b) \) ko'rinishida ekani sababli, har ikki kvadratdan farq funksiyasidan foydalanamiz. Birinchi qism: \( 71^2 - 23^2 = (71 - 23)(71 + 23) = 48 \cdot 94 = 4512 \). Ikkinchi qism: \( 62^2 - 32^2 = (62 - 32)(62 + 32) = 30 \cdot 94 = 2820 \). Ko'rinadi \( 4512 + 94 \cdot 42 = 4512 + 3948 = 8460 \) va \( \frac{8460}{2820} = 3 \). Shuning uchun, to'g'ri javob C) 3.