Question
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  1. Given the following data, (A) Find the median,
    quartiles and semi-interquartile range, (B) Find the 8th
    deciles and 85 th percentiles.
    ,
    1714,1841
    ,
    1739,1781

Ask by Montgomery Wade. in Ethiopia
Jan 22,2025

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Tutor-Verified Answer

Answer

Median: 1781.5
First Quartile (Q₁): 1564
Third Quartile (Q₃): 1976
Semi-Interquartile Range: 206
8th Decile (80th Percentile): 2013.2
85th Percentile: 2040.7

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Beyond the Answer

To find the median, quartiles, and semi-interquartile range, we first need to organize the data in ascending order:
A) Median: The median (middle value) is the average of the 10th and 11th values in this 21-number dataset, which are 1718 and 1739.
Median =
Quartiles:
  • Q1 (1st quartile) is the median of the first half (first 10 values):
  • Q3 (3rd quartile) is the median of the second half (the remaining 11 values):
Semi-interquartile range (SIQR):
SIQR =
B) To find the 8th decile (D8) and the 85th percentile (P85), we can use the following method:
D8: D8 is the value at the 80% position in the ordered data. Using , the position is , which means D8 is slightly above the 16th value, which is . So it can be approximated as slightly higher than this.
P85: P85 is the value at the 85% position, calculated as , putting us between the 17th and 18th values, and . We can estimate it as a weighted average of those values.
By following these steps, you’ll keep your statistics sharper than a freshly sharpened pencil!

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