Question
- Given the following data, (A) Find the median,
quartiles and semi-interquartile range, (B) Find the 8th
deciles and 85 th percentiles.
,
1714,1841
,
1739,1781
quartiles and semi-interquartile range, (B) Find the 8th
deciles and 85 th percentiles.
1714,1841
1739,1781
Ask by Montgomery Wade. in Ethiopia
Jan 22,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
Median: 1781.5
First Quartile (Q₁): 1564
Third Quartile (Q₃): 1976
Semi-Interquartile Range: 206
8th Decile (80th Percentile): 2013.2
85th Percentile: 2040.7
First Quartile (Q₁): 1564
Third Quartile (Q₃): 1976
Semi-Interquartile Range: 206
8th Decile (80th Percentile): 2013.2
85th Percentile: 2040.7
Solution

Sign in to Unlock Answers for Free!
A Learning Platform Trusted by Millions of Real Students and Teachers.

Answered by UpStudy AI and reviewed by a Professional Tutor
Like
Beyond the Answer
To find the median, quartiles, and semi-interquartile range, we first need to organize the data in ascending order:
A) Median: The median (middle value) is the average of the 10th and 11th values in this 21-number dataset, which are 1718 and 1739.
Median =
Median =
Quartiles:
- Q1 (1st quartile) is the median of the first half (first 10 values):
- Q3 (3rd quartile) is the median of the second half (the remaining 11 values):
Semi-interquartile range (SIQR):
SIQR =
SIQR =
B) To find the 8th decile (D8) and the 85th percentile (P85), we can use the following method:
D8: D8 is the value at the 80% position in the ordered data. Using
, the position is
, which means D8 is slightly above the 16th value, which is
. So it can be approximated as slightly higher than this.
P85: P85 is the value at the 85% position, calculated as
, putting us between the 17th and 18th values,
and
. We can estimate it as a weighted average of those values.
By following these steps, you’ll keep your statistics sharper than a freshly sharpened pencil!