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Draw resonance structures for \( \mathrm{CO}^{2-} \), showing the delocalization of charge using curved arrows. QUESTION 6 Calculate the amount of sed um hydroxide that is needec-to prepare one itre of a 350 molar sodium hydroride solution.

Ask by Graham Gibson. in South Africa
Jan 21,2025

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To prepare 1 litre of a 0.350 M sodium hydroxide (NaOH) solution, you need 14.00 grams of solid NaOH.

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To draw the resonance structures for \( \mathrm{CO}^{2-} \) (carbonate ion), you can start with one structure where the carbon is double-bonded to one oxygen and single-bonded to the other two oxygens, which each carry a negative charge. Then, you create two additional resonance structures by shifting the double bond between carbon and an oxygen in the direction of one of the negatively charged oxygens. Use curved arrows to show the movement of electrons during this process, highlighting the delocalization of the negative charge across the oxygen atoms. To prepare a 350 M solution of sodium hydride (\( \text{NaH} \)), you need to calculate the necessary amount of sodium hydroxide (\( \text{NaOH} \)) since they are equivalently reacting species. A 350 M solution means you need 350 moles of sodium hydroxide in one liter. Given that \( \text{NaOH} \) has a molar mass of about 40 g/mol, you would need 350 moles × 40 g/mol = 14,000 g of sodium hydroxide to make one liter of this highly concentrated solution. Quite a hefty amount, so definitely handle with care!

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