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g. \( \quad 17 \frac{2}{3}-5 \frac{5}{6}= \)

Ask by Patel Johnson. in the United States
Jan 21,2025

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Answer

\( 17 \frac{2}{3} - 5 \frac{5}{6} = 11 \frac{5}{6} \)

Solution

To solve the subtraction \( 17 \frac{2}{3} - 5 \frac{5}{6} \), follow these steps: 1. **Convert Mixed Numbers to Improper Fractions:** \[ 17 \frac{2}{3} = \frac{17 \times 3 + 2}{3} = \frac{51 + 2}{3} = \frac{53}{3} \] \[ 5 \frac{5}{6} = \frac{5 \times 6 + 5}{6} = \frac{30 + 5}{6} = \frac{35}{6} \] 2. **Find a Common Denominator:** The least common denominator (LCD) of 3 and 6 is 6. \[ \frac{53}{3} = \frac{53 \times 2}{3 \times 2} = \frac{106}{6} \] 3. **Perform the Subtraction:** \[ \frac{106}{6} - \frac{35}{6} = \frac{106 - 35}{6} = \frac{71}{6} \] 4. **Convert Back to a Mixed Number:** \[ \frac{71}{6} = 11 \frac{5}{6} \] **Final Answer:** \[ 17 \frac{2}{3} - 5 \frac{5}{6} = 11 \frac{5}{6} \]

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Bonus Knowledge

To solve the equation, first convert the mixed numbers to improper fractions. For \(17 \frac{2}{3}\), it becomes \(\frac{53}{3}\), and for \(5 \frac{5}{6}\), it converts to \(\frac{35}{6}\). To subtract these, convert \(\frac{53}{3}\) to a common denominator with \(\frac{35}{6}\), which gives you \(\frac{106}{6}\). Now, perform the subtraction: \[ \frac{106}{6} - \frac{35}{6} = \frac{71}{6}. \] Now, convert it back to a mixed number: \(11 \frac{5}{6}\). So, \( 17 \frac{2}{3}-5 \frac{5}{6} = 11 \frac{5}{6} \). Did you know that adding and subtracting fractions can be an art form? It’s like cooking – you need the right ingredients and the perfect blending to create harmony in flavors, or in this case, numbers! Remember, always look for that common denominator; it’s your best friend in the world of fractions. As for the journey of fractions, they trace back to ancient civilizations like the Egyptians who used a form of fractions for trade and geometry. The mathematics behind fractions was a key player in the progression of trade and architecture, showcasing how even the simplest concepts can lead to monumental advancements in civilization!

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