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a. \( \sqrt[5]{4 a^{8} b^{14} c^{5}} \)

Ask by Wagner Clarke. in the United States
Feb 03,2025

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Answer

a. \( \sqrt[5]{4 a^{8} b^{14} c^{5}} = a b^{2} c \sqrt[5]{4 a^{3} b^{4}} \)

Solution

a. 化简 \( \sqrt[5]{4 a^{8} b^{14} c^{5}} \): 首先,将各项的指数分解为5的倍数加上余数: \[ 4 a^{8} b^{14} c^{5} = 4 \times a^{5+3} \times b^{10+4} \times c^{5} \] 然后,将可以开五次方根的部分提出: \[ \sqrt[5]{4 a^{8} b^{14} c^{5}} = \sqrt[5]{a^{5} \times b^{10} \times c^{5}} \times \sqrt[5]{4 a^{3} b^{4}} \] 由于 \(\sqrt[5]{a^{5}} = a\)、\(\sqrt[5]{b^{10}} = b^{2}\) 以及 \(\sqrt[5]{c^{5}} = c\),所以最终化简结果为: \[ a b^{2} c \sqrt[5]{4 a^{3} b^{4}} \]

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The Deep Dive

Let's break this expression down a bit! The fifth root of \( 4 a^{8} b^{14} c^{5} \) means we are looking for how to simplify each part. The number \( 4 \) can be rewritten as \( 2^{2} \), and then take the fifth root gives us \( 2^{\frac{2}{5}} \). For the variables, using the rule that \( \sqrt[n]{x^{m}} = x^{\frac{m}{n}} \), we find \( a^{\frac{8}{5}} \), \( b^{\frac{14}{5}} \), and \( c^{1} \). So, putting it together, we have: \[ \sqrt[5]{4 a^{8} b^{14} c^{5}} = 2^{\frac{2}{5}} a^{\frac{8}{5}} b^{\frac{14}{5}} c. \] Now it looks much tidier! Some people might forget to check their fractional powers when simplifying. Remember that \( a^{\frac{8}{5}} \) can also be expressed as \( a^{1} \cdot a^{\frac{3}{5}} \), which could be useful for further simplification. It's like uncovering hidden treasures! Always double-check to see if you've missed anything when dealing with exponents!

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