Question
What are the square roots of \( \frac{9}{2500} ? \) Write your answers as proper fractions, improper fractions, or whole numbers. Submit
Ask by Perkins Lang. in the United States
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
The square roots of \( \frac{9}{2500} \) are \( \frac{3}{50} \) and \( -\frac{3}{50} \).
Solution
To find the square roots of \( \frac{9}{2500} \), we can take the square root of the numerator and the denominator separately:
\[
\sqrt{\frac{9}{2500}} = \frac{\sqrt{9}}{\sqrt{2500}} = \frac{3}{50}
\]
However, both positive and negative values are square roots of a number. Therefore, the square roots of \( \frac{9}{2500} \) are:
\[
\frac{3}{50} \quad \text{and} \quad -\frac{3}{50}
\]
**Answer:** \( \frac{3}{50} \) and \( -\frac{3}{50} \)
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Simplify this solution Bonus Knowledge
The square roots of \( \frac{9}{2500} \) can be calculated by taking the square roots of the numerator and the denominator separately. The square root of 9 is 3, and the square root of 2500 is 50. Therefore, the square roots of \( \frac{9}{2500} \) are: \[ \frac{\sqrt{9}}{\sqrt{2500}} = \frac{3}{50} \] Since we can also have a negative square root, the results are: \[ \frac{3}{50} \quad \text{and} \quad -\frac{3}{50} \]
