Question
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10. Given the prime factorisation of each of the following numbers, find its square root without using a calculator. \( \begin{array}{ll}\text { (a) } 9801=3^{4} \times 11^{2} & \text { (b) } 35721=3^{6} \times 7^{2}\end{array} \)

Ask by Bartlett Page. in Singapore
Jan 22,2025

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Tutor-Verified Answer

Answer

The square roots are: - (a) √9801 = 99 - (b) √35721 = 189

Solution

To find the square roots of the given numbers using their prime factorizations, follow these steps: ### (a) \(9801 = 3^{4} \times 11^{2}\) 1. **Understand the Square Root of a Product:** \[ \sqrt{a \times b} = \sqrt{a} \times \sqrt{b} \] 2. **Apply the Square Root to Each Prime Factor:** \[ \sqrt{3^{4} \times 11^{2}} = \sqrt{3^{4}} \times \sqrt{11^{2}} \] 3. **Simplify Each Square Root:** \[ \sqrt{3^{4}} = 3^{2} = 9 \] \[ \sqrt{11^{2}} = 11 \] 4. **Multiply the Results:** \[ 9 \times 11 = 99 \] **So, \(\sqrt{9801} = 99\).** --- ### (b) \(35721 = 3^{6} \times 7^{2}\) 1. **Understand the Square Root of a Product:** \[ \sqrt{a \times b} = \sqrt{a} \times \sqrt{b} \] 2. **Apply the Square Root to Each Prime Factor:** \[ \sqrt{3^{6} \times 7^{2}} = \sqrt{3^{6}} \times \sqrt{7^{2}} \] 3. **Simplify Each Square Root:** \[ \sqrt{3^{6}} = 3^{3} = 27 \] \[ \sqrt{7^{2}} = 7 \] 4. **Multiply the Results:** \[ 27 \times 7 = 189 \] **So, \(\sqrt{35721} = 189\).** --- **Final Answers:** - **(a)** \(\sqrt{9801} = 99\) - **(b)** \(\sqrt{35721} = 189\)

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To find the square root of \( 9801 = 3^{4} \times 11^{2} \), we can take the square root of each prime factor. The square root of \( 3^{4} \) is \( 3^{2} = 9 \), and the square root of \( 11^{2} \) is \( 11^{1} = 11 \). So, the square root of \( 9801 \) is \( 9 \times 11 = 99 \). For \( 35721 = 3^{6} \times 7^{2} \), we apply the same method. The square root of \( 3^{6} \) is \( 3^{3} = 27 \), and the square root of \( 7^{2} \) is \( 7^{1} = 7 \). Therefore, the square root of \( 35721 \) is \( 27 \times 7 = 189 \). So, the square roots are: (a) \( \sqrt{9801} = 99 \) (b) \( \sqrt{35721} = 189 \)

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