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Which exponential functions have been simplified correctly? Check all that apply. \( f(x)=5 \sqrt[3]{16}^{x}=5(2 \sqrt[3]{2})^{x} \) \( f(x)=2.3(8)^{\frac{1}{2} x}=2.3(4)^{x} \) \( f(x)=81^{\frac{x}{4}}=3^{x} \) \( f(x)=\frac{3}{4} \sqrt{27^{x}}=\frac{3}{4}(3 \sqrt{3})^{x} \) \( f(x)=(24)^{\frac{1}{3} x}=2(\sqrt[3]{3})^{x} \)

Ask by Nunez Wood. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The correctly simplified exponential functions are the first, third, and fourth options.

Solution

Let's analyze each exponential function to determine if it has been simplified correctly. 1. **\( f(x)=5 \sqrt[3]{16}^{x}=5(2 \sqrt[3]{2})^{x} \)** - **Original Expression:** \( 5 \cdot 16^{\frac{1}{3}x} \) - **Simplification:** \( 5 \cdot (2 \cdot 2^{\frac{1}{3}})^x = 5 \cdot (2^{\frac{4}{3}})^x = 5 \cdot 2^{\frac{4}{3}x} \) Since \( 16^{\frac{1}{3}} = 2 \sqrt[3]{2} \), the simplification is **correct**. 2. **\( f(x)=2.3(8)^{\frac{1}{2} x}=2.3(4)^{x} \)** - **Original Expression:** \( 2.3 \cdot 8^{\frac{1}{2}x} = 2.3 \cdot (2 \sqrt{2})^x \) - **Simplification:** \( 2.3 \cdot 4^x \) However, \( 8^{\frac{1}{2}} = 2 \sqrt{2} \), not \( 4 \). Therefore, the simplification is **incorrect**. 3. **\( f(x)=81^{\frac{x}{4}}=3^{x} \)** - **Original Expression:** \( 81^{\frac{x}{4}} = (3^4)^{\frac{x}{4}} = 3^x \) The simplification is **correct**. 4. **\( f(x)=\frac{3}{4} \sqrt{27^{x}}=\frac{3}{4}(3 \sqrt{3})^{x} \)** - **Original Expression:** \( \frac{3}{4} \cdot 27^{\frac{x}{2}} = \frac{3}{4} \cdot (3 \sqrt{3})^x \) Since \( 27^{\frac{1}{2}} = 3 \sqrt{3} \), the simplification is **correct**. 5. **\( f(x)=(24)^{\frac{1}{3} x}=2(\sqrt[3]{3})^{x} \)** - **Original Expression:** \( 24^{\frac{x}{3}} = (2^3 \cdot 3)^{\frac{x}{3}} = 2^x \cdot 3^{\frac{x}{3}} \) - **Simplification:** \( 2 \cdot 3^{\frac{x}{3}} \) These are not equivalent unless \( x = 1 \). Therefore, the simplification is **incorrect**. **In summary, the correctly simplified exponential functions are the first, third, and fourth options.** **Answer:** All except the second and fifth functions are simplified correctly.

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The Deep Dive

Let’s break down the options step by step to see which functions have been simplified correctly! For the first function: \( f(x)=5 \sqrt[3]{16}^{x}=5(2 \sqrt[3]{2})^{x} \) is actually not correct since \( \sqrt[3]{16} \neq 2 \sqrt[3]{2} \). The second function \( f(x)=2.3(8)^{\frac{1}{2} x}=2.3(4)^{x} \) is incorrect as \( (8)^{\frac{1}{2} x} \) simplifies to \( (2^3)^{\frac{1}{2} x} = (2^{1.5})^x \) which does not equal \( (4)^x \). The third option \( f(x)=81^{\frac{x}{4}}=3^{x} \) is also incorrect, as \( 81^{\frac{x}{4}} \) simplifies to \( (3^4)^{\frac{x}{4}} = 3^x \) and not \( 3^x \). For the fourth option \( f(x)=\frac{3}{4} \sqrt{27^{x}}=\frac{3}{4}(3 \sqrt{3})^{x} \), this is correct because \( \sqrt{27^{x}} = (27^{\frac{1}{2}})^x = (3^{\frac{3}{2}})^x = 3^{\frac{3}{2}x} = 3^{x} \cdot \sqrt{3} \), which fits. Finally, \( f(x)=(24)^{\frac{1}{3} x}=2(\sqrt[3]{3})^{x} \) doesn’t hold since \( (24)^{\frac{1}{3} x} = (2^3 \cdot 3)^{\frac{1}{3} x} = 2^x \cdot 3^{\frac{1}{3} x} \). Therefore, it’s not correct either. In short, only the fourth function is simplified correctly while the others have mistakes in their simplifications. Happy simplifying!

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