What is wrong with the following code fragment? char str1[10] = "Mark", str2[15] = "What's my name"; strcpy \( (\operatorname{str} 1 \), str2); str1 does not have enough room. nothing str2 has white space in it. str2 does not have enough room.

The issue with the provided code lies in the `strcpy` operation: ```c char str1[10] = "Mark", str2[15] = "What's my name"; strcpy(str1, str2); ``` **Breaking it down:** 1. **Initialization:** - `str1` is allocated 10 characters and initialized with `"Mark"` (which uses 5 characters including the null terminator `\0`). - `str2` is allocated 15 characters and initialized with `"What's my name"`. 2. **Copy Operation:** - The `strcpy(str1, str2);` attempts to copy the contents of `str2` into `str1`. 3. **Problem:** - The string `"What's my name"` consists of 14 characters (including the null terminator). - `str1` only has space for 10 characters. - This results in a **buffer overflow**, as `str1` cannot accommodate the entire content of `str2`. **Correct Option:** - **str1 does not have enough room.** **Recommendation:** - Ensure that the destination array (`str1`) has sufficient space to hold the source string plus the null terminator. For example: ```c char str1[15] = "Mark", str2[15] = "What's my name"; strcpy(str1, str2); ``` Alternatively, consider using `strncpy` to prevent buffer overflows by specifying the maximum number of characters to copy. **Answer:** str1 does not have enough room.