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\( 1 \leftarrow \quad \) Solve the quadratic equation \( 36=(x+4)^{2} \)

Ask by Ross Best. in the United States
Jan 24,2025

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Answer

The solutions are \( x = 2 \) and \( x = -10 \).

Solution

To solve the quadratic equation: \[ 36 = (x + 4)^2 \] **Step 1: Take the Square Root of Both Sides** \[ \sqrt{36} = \sqrt{(x + 4)^2} \] \[ 6 = |x + 4| \] This implies two possible equations: \[ x + 4 = 6 \quad \text{or} \quad x + 4 = -6 \] **Step 2: Solve Each Equation Separately** 1. **First Equation:** \[ x + 4 = 6 \] Subtract 4 from both sides: \[ x = 6 - 4 \] \[ x = 2 \] 2. **Second Equation:** \[ x + 4 = -6 \] Subtract 4 from both sides: \[ x = -6 - 4 \] \[ x = -10 \] **Solution:** The quadratic equation \( 36 = (x + 4)^2 \) has two solutions: \[ x = 2 \quad \text{and} \quad x = -10 \]

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To solve the equation \( 36 = (x + 4)^{2} \), we first take the square root of both sides. This gives us two cases to consider: 1. \( x + 4 = 6 \) 2. \( x + 4 = -6 \) For the first case, subtracting 4 from both sides gives \( x = 2 \). For the second case, subtracting 4 gives \( x = -10 \). Thus, the solutions are \( x = 2 \) and \( x = -10 \)! Isn’t it neat how squaring an expression can lead to two different solutions? Quadratics often open up a world of possibilities!

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