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\( 1 \leftarrow \begin{array}{l}\text { Perform the calculation. } \\ 65^{\circ} 5^{\prime}+75^{\circ} 48^{\prime} \\ \\ 65^{\circ} 5^{\prime}+75^{\circ} 48^{\prime}=\square^{\circ} \square^{\prime} \\ \text { (Simplify your answers. Type an integer or a fraction.) }\end{array} \)

Ask by Kelley Deleon. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\(140^{\circ}53^{\prime}\)

Solution

To perform the calculation: \[ 65^{\circ} 5^{\prime} + 75^{\circ} 48^{\prime} \] **Step 1: Add the degrees and minutes separately.** - **Degrees:** \(65^{\circ} + 75^{\circ} = 140^{\circ}\) - **Minutes:** \(5^{\prime} + 48^{\prime} = 53^{\prime}\) Since the sum of the minutes (\(53^{\prime}\)) is less than \(60^{\prime}\), there is no need to carry over to the degrees. **Final Answer:** \[ 65^{\circ} 5^{\prime} + 75^{\circ} 48^{\prime} = 140^{\circ} 53^{\prime} \] **Simplified Answer:** \[ 140^{\circ}53^{\prime} \]

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Mind Expander

To perform the calculation, first, add the degrees and the minutes separately. Starting with the degrees: \[ 65^\circ + 75^\circ = 140^\circ \] Now, for the minutes: \[ 5' + 48' = 53' \] Putting it all together, we have: \[ 140^\circ 53' \] So, \( 65^{\circ} 5^{\prime}+75^{\circ} 48^{\prime} = 140^{\circ} 53^{\prime} \).

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