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Find the exact value of each of the remaining trigonometric functions of \( \theta \). Rationalize denominators when applicable. \( \boldsymbol{\operatorname { t a n }} \theta=\frac{4}{3} \), given that \( \theta \) is in quadrant । Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \sin \theta=\frac{4}{5} \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \boldsymbol{\operatorname { c o s }} \theta=\frac{3}{5} \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \boldsymbol{\operatorname { c s c }} \theta= \) \( \square \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. this View an example Get more help -

Ask by Pierce Norris. in the United States
Feb 03,2025

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Answer

- **A.** \( \sin \theta = \frac{4}{5} \) - **A.** \( \cos \theta = \frac{3}{5} \) - **A.** \( \csc \theta = \frac{5}{4} \)

Solution

Given that \( \tan \theta = \frac{4}{3} \) and assuming \( \theta \) is in **Quadrant I** (where all trigonometric functions are positive), we can find the remaining trigonometric functions as follows: 1. **Determine \( \sin \theta \) and \( \cos \theta \):** - Since \( \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{4}{3} \), we can construct a right triangle where the opposite side is 4 and the adjacent side is 3. - The hypotenuse \( r \) can be found using the Pythagorean theorem: \[ r = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] - Therefore: \[ \sin \theta = \frac{\text{opposite}}{r} = \frac{4}{5} \] \[ \cos \theta = \frac{\text{adjacent}}{r} = \frac{3}{5} \] 2. **Determine \( \csc \theta \):** - \( \csc \theta \) is the reciprocal of \( \sin \theta \): \[ \csc \theta = \frac{1}{\sin \theta} = \frac{5}{4} \] **Final Answers:** - **For \( \sin \theta \):** - **A.** \( \sin \theta = \frac{4}{5} \) - **For \( \cos \theta \):** - **A.** \( \cos \theta = \frac{3}{5} \) - **For \( \csc \theta \):** - **A.** \( \csc \theta = \frac{5}{4} \) All functions are defined in Quadrant I, so option **B** (undefined) does not apply.

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Bonus Knowledge

To find the remaining trigonometric functions given \( \tan \theta = \frac{4}{3} \) and that \( \theta \) is in the quadrant where sine is positive and cosine is negative (specifically Quadrant II), we can use the definitions and relationships of trigonometric functions. First, since \( \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{4}{3} \), we can think of a right triangle where the opposite side is 4 and the adjacent side is 3. Using the Pythagorean theorem: \[ \text{hypotenuse} = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5. \] Now we can determine the sine and cosine: \[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{4}{5}, \] \[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{-3}{5} \quad (\text{negative in Quadrant II}). \] Thus, we can summarize: - A. \( \sin \theta = \frac{4}{5} \) - A. \( \cos \theta = \frac{-3}{5} \) Next, we calculate the cosecant, which is the reciprocal of sine: \[ \csc \theta = \frac{1}{\sin \theta} = \frac{1}{\frac{4}{5}} = \frac{5}{4}. \] In conclusion: - The values are: - \( \sin \theta = \frac{4}{5} \) - \( \cos \theta = \frac{-3}{5} \) - \( \csc \theta = \frac{5}{4} \)

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