Question
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\( 18 a ^ { 2 } - 27 a b + 14 a c - 216 c = \)

Ask by Salazar Cruz. in Turkey
Jan 23,2025

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Tutor-Verified Answer

Answer

Выражение \( 18a^{2} - 27ab + 14ac - 216c \) уже упрощено. Результат: \[ 18a^{2} - 27ab + 14ac - 216c \]

Solution

Simplify the expression by following steps: - step0: Solution: \(18a^{2}-27ab+14ac-216c\) Выражение \( 18 a ^ { 2 } - 27 a b + 14 a c - 216 c \) уже является упрощённым. Таким образом, результат: \[ 18a^{2} - 27ab + 14ac - 216c \]

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Bonus Knowledge

To factor the expression \(18 a^2 - 27 ab + 14 ac - 216c\), let's look for common factors first. The terms can be rearranged and grouped: 1. Group the first two terms and the last two terms: \((18a^2 - 27ab) + (14ac - 216c)\) 2. Factor out the common factors in each group: - From the first group \(18a^2 - 27ab\), you can factor out \(9a\), giving you: \(9a(2a - 3b)\) - From the second group \(14ac - 216c\), factor out \(2c\): \(2c(7a - 108)\) Putting it together, it looks like we can't factor it further directly because \(2a - 3b\) and \(7a - 108\) don’t yield a common factor easily. Thus, as is, the expression doesn't simplify neatly into clean factors. So the simplified expression remains \(18a^2 - 27ab + 14ac - 216c\), and you might need to check it for specific values of \(a, b, c\) for further insights! 📚✨

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