domain and range \( h(x)=\left\{\begin{array}{ll}x^{2}, & -3 \leq x<3 \\ 2-x, & 3 \leq x<7\end{array}\right. \)
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Beyond the Answer
For the function \( h(x) \), let's break it down! For the first part, where \( -3 \leq x < 3 \), the output is \( x^2 \), which ranges from \( 0 \) (when \( x = 0 \)) to \( 9 \) (when \( x = 3 \), although 3 is not included). So, the range here is \( [0, 9) \). In the second part, \( 2-x \), where \( 3 \leq x < 7 \), the output goes from \( -1 \) (when \( x = 3 \)) to \( -5 \) (when \( x \) approaches 7). Thus, this segment’s range is \( (-5, -1] \). Combining these, the overall range of \( h(x) \) is \( [0, 9) \cup (-5, -1] \). The domain of \( h(x) \) can be easily identified since it includes all values from \( -3 \) to \( 7 \), taken as \( -3 \leq x < 7 \). Therefore, the domain is simply \( [-3, 7) \). This means you can plug in any x-value from \(-3\) up to, but not including, \(7\), and you'll get a real number output!