Question
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(9) \( 2 x^{2}-5 x-3= \)

Ask by Dawson Bolton. in Australia
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The solutions are \( x = -0.5 \) and \( x = 3 \).

Solution

Solve the quadratic equation by following steps: - step0: Solve by factoring: \(2x^{2}-5x-3=0\) - step1: Factor the expression: \(\left(x-3\right)\left(2x+1\right)=0\) - step2: Separate into possible cases: \(\begin{align}&x-3=0\\&2x+1=0\end{align}\) - step3: Solve the equation: \(\begin{align}&x=3\\&x=-\frac{1}{2}\end{align}\) - step4: Rewrite: \(x_{1}=-\frac{1}{2},x_{2}=3\) To solve the equation \( 2x^{2} - 5x - 3 = 0 \), we can use the quadratic formula or factorization. Here, I will provide the solutions directly. The solutions to the equation are: - \( x_{1} = -\frac{1}{2} \) - \( x_{2} = 3 \) Thus, the values of \( x \) that satisfy the equation are \( -0.5 \) and \( 3 \).

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Beyond the Answer

To solve the quadratic equation \( 2x^2 - 5x - 3 = 0 \), you can use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Here, \( a = 2 \), \( b = -5 \), and \( c = -3 \). Plugging in these values, compute the discriminant \( b^2 - 4ac = (-5)^2 - 4(2)(-3) \), which simplifies to \( 25 + 24 = 49 \). Solving gives you two possible values for \( x \): \( 3 \) and \( -\frac{1}{2} \). Quadratic equations like this one pop up all the time in the real world! Whether you're calculating the trajectory of a basketball, optimizing a design in engineering, or even determining the best pricing strategy for a product, these equations help make sense of various scenarios. Understanding them can give you the edge to tackle problems in physics, economics, and beyond! When using the quadratic formula, remember to double-check your calculations—it's easy to make a mistake under pressure! Also, ensure that the discriminant is non-negative; if it’s negative, there are no real solutions. Lastly, always verify your answers by plugging them back into the original equation to see if they actually satisfy it. Happy solving!

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