$$ Cu + HNO _ { 3 } \rightarrow Cu ( NO _ { 3 } ) _ { 2 } + NO + H _ { 2 } O $$

Question

UpStudy AI · Accepted Answer

To balance the chemical equation $$ Cu + HNO_3 \rightarrow Cu(NO_3)_2 + NO + H_2O $$, we will follow these steps:

1. **Identify the number of atoms of each element on both sides of the equation.**
2. **Balance the equation by adjusting coefficients.**
3. **Ensure that the number of atoms for each element is the same on both sides.**

### Step 1: Count the Atoms

- **Reactants:**
  - Cu: 1
  - H: 1
  - N: 1
  - O: 3

- **Products:**
  - Cu: 1 (in $$ Cu(NO_3)_2 $$)
  - H: 2 (in $$ H_2O $$)
  - N: 2 (1 in $$ Cu(NO_3)_2 $$ and 1 in $$ NO $$)
  - O: 7 (6 in $$ Cu(NO_3)_2 $$ and 1 in $$ H_2O $$)

### Step 2: Balancing the Equation

1. **Balance Copper (Cu):** 
   - Cu is already balanced (1 on each side).

2. **Balance Nitrogen (N):**
   - There are 2 N in the products (1 from $$ Cu(NO_3)_2 $$ and 1 from $$ NO $$), so we need 2 $$ HNO_3 $$ in the reactants.
   - Update the equation: 
   $$
   Cu + 2 HNO_3 \rightarrow Cu(NO_3)_2 + NO + H_2O
   $$

3. **Balance Hydrogen (H):**
   - Now we have 2 H in the reactants (from $$ 2 HNO_3 $$) and 2 H in the products (from $$ H_2O $$), so H is balanced.

4. **Balance Oxygen (O):**
   - Reactants: $$ 2 HNO_3 $$ gives 6 O.
   - Products: $$ Cu(NO_3)_2 $$ gives 6 O and $$ H_2O $$ gives 1 O, totaling 7 O.
   - We need to adjust the number of $$ H_2O $$ to balance the O. We already have 6 O from $$ Cu(NO_3)_2 $$ and need 1 more from $$ H_2O $$, so we can keep it as is.

### Final Balanced Equation

The balanced equation is:
$$
Cu + 4 HNO_3 \rightarrow Cu(NO_3)_2 + 2 NO + 2 H_2O
$$

### Summary

The balanced chemical equation is:
$$
Cu + 4 HNO_3 \rightarrow Cu(NO_3)_2 + 2 NO + 2 H_2O
$$

This ensures that the number of atoms for each element is the same on both sides of the equation.
The balanced chemical equation is: $$ Cu + 4 HNO_3 \rightarrow Cu(NO_3)_2 + 2 NO + 2 H_2O $$

\( Cu + HNO _ { 3 } \rightarrow Cu ( NO _ { 3 } ) _ { 2 } + NO + H _ { 2 } O \)

Real Tutor Solution

Answer

Solution

The Deep Dive

Related Questions

Latest Chemistry Questions