Give the prime factors of the following numbers (use the lacder or treo mothod is find them \( \begin{array}{llll}\text { a) } 183 & \text { b) } 535 & \text { c) } \\ \text { d) } 484 & \text { e) } & 633 & \text { 1) }\end{array} \)

Sure! Let's find the prime factors of each number using the **ladder method** (also known as the factor tree method). This method involves breaking down the number step by step into its prime factors. ### a) \(183\) 1. **Check divisibility by 3**: - Sum of digits: \(1 + 8 + 3 = 12\) (which is divisible by 3) - \(183 \div 3 = 61\) 2. **Check if 61 is prime**: - 61 is a prime number. **Prime Factors of 183**: \[ 183 = 3 \times 61 \] --- ### b) \(535\) 1. **Check divisibility by 5**: - The last digit is 5, so it's divisible by 5. - \(535 \div 5 = 107\) 2. **Check if 107 is prime**: - 107 is a prime number. **Prime Factors of 535**: \[ 535 = 5 \times 107 \] --- ### d) \(484\) 1. **Check divisibility by 2**: - 484 is even, so it's divisible by 2. - \(484 \div 2 = 242\) 2. **Divide 242 by 2 again**: - \(242 \div 2 = 121\) 3. **Factorize 121**: - \(121 = 11 \times 11\) - 11 is a prime number. **Prime Factors of 484**: \[ 484 = 2 \times 2 \times 11 \times 11 = 2^2 \times 11^2 \] --- ### e) \(633\) 1. **Check divisibility by 3**: - Sum of digits: \(6 + 3 + 3 = 12\) (which is divisible by 3) - \(633 \div 3 = 211\) 2. **Check if 211 is prime**: - 211 is a prime number. **Prime Factors of 633**: \[ 633 = 3 \times 211 \] --- If there was a part **c)** intended, please provide the number, and I'll be happy to help factorize it!